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Igoryamba
3 years ago
13

Which has more pressure, FIRST one gets all the points.

Physics
1 answer:
SSSSS [86.1K]3 years ago
8 0

<u>Answer:</u>

area of point has more pressure.

<u>Explanation:</u>

formula's : pressure = force ÷ area

1st pressure,

200 ÷ 0.2 = 1000 Pa

2nd pressure,

200 ÷ 0.004 = 50000 Pa

<h3>Therefore the pressure on the area of the point is more.</h3>
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A code of ethics is a set of principles and rules used by individuals and organizations to govern their decision making process, as well as to distinguish right from wrong. These codes are often more complex and contextual than simple morality, acknowledging specific situations and providing guidance. Many codes of ethics also specify penalties for violations. Professional and personal codes of ethics ensure that adherents are behaving in a socially acceptable manner. Organizations with an established code of ethics usually have review processes and appeal procedures in place to guard against malicious or self-serving use of the code.
8 0
3 years ago
If you push on a railroad boxcar with a force of 200 N and it doesn’t move, you can conclude that
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4 years ago
Calculate the kinetic energy of a truck that has a mass of 2400kg and is moving at 15m/s
Norma-Jean [14]

Answer:

Given,

Explanation:

mass(m)=2400kg

velocity(v)=15m/s

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3 0
3 years ago
An archer draws her bow and stores 34.8 J of elastic potential energy in the bow. She releases the 63 g arrow, giving it an init
elena-14-01-66 [18.8K]

Answer:

Approximately 71\%.

Explanation:

The formula for the kinetic energy \rm KE of an object is:

\displaystyle \mathrm{KE} = \frac{1}{2}\, m \cdot v^2,

where

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  • v is the speed of that object.

Important: Joule (\rm J) is the standard unit for energy. The formula for \rm KE requires two inputs: mass and speed. The standard unit of mass is \rm kg while the standard unit for speed is \rm m \cdot s^{-1}. If both inputs are in standard units, then the output (kinetic energy) will also be in the standard unit (that is: joules,

Convert the unit of the arrow's mass to standard unit:

m = 63\; \rm g = 0.063\; \rm kg.

Initial \rm KE of this arrow:

\begin{aligned}\mathrm{KE} &= \frac{1}{2} \, m \cdot v^2 \\ &= \frac{1}{2}\times 0.063\; \rm kg \times \left(\rm 28 \; m \cdot s^{-1}\right)^2 \\ &\approx 24.696\; \rm J\end{aligned}.

That's the same as the energy output of this bow. Hence, the efficiency of energy transfer will be:

\displaystyle \frac{24.696\; \rm J}{34.8\; \rm J} \times 100\% \approx 71\%.

8 0
4 years ago
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