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3 years ago

What is the volume? Plzzz help

Mathematics

1 answer:

snow_tiger [21]3 years ago

8 0

Answer:

618.75 yd

Step-by-step explanation:

12 3/8 = 12.375

12.375 X 10 X 5 = 618.75

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12 side solid is Rolled 200 times how many times would you expect either a 4,6,9 to be Rolled

Naddika [18.5K]

A 4,6, or 9 will be rolled at least 5.5 times each.

8 0

3 years ago

Which of the following is the inverse of y=6^x?

atroni [7]

Rearrange so

x=f(x)/6

then invert

f^-1(x)=x/6

8 0

3 years ago

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Help help help help!!!!!

Dovator [93]

Answer:

9 1/3

Step-by-step explanation:

As you may know, when you divide a positive number by a negative number, the quotient (result of the division) is negative.

Knowing this, all you have to do is divide the numbers normally as positive numbers and then add a negative sign at the end.

To divide fractions, you change the sign to multiplication and multiply the first number by the reciprocal of the second number.

The reciprocal is just the "flipped" version of a fraction.

For example, the reciprocal of 3/4 would be 4/3.

In this problem, you can't reduce.

So, just multiply the top numbers and do the same with the bottom numbers.

That would be $\frac{35*4}{5*3}$ .

35*4=140 and 5*3=15.

The fraction would be 140/15

You can divide 140 by 15, which would be 9 and 1/3

6 0

3 years ago

What is 3(x+3)-10=32 solving for x and in set notations ?

Mazyrski [523]

Answer:

x=11

Step-by-step explanation:

4 0

3 years ago

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What are the solutions of x^2-2x+5=0

sweet [91]

The solution of $x^{2}-2 x+5=0$ are 1 + 2i and 1 – 2i

Solution:

Given, equation is $x^{2}-2 x+5=0$

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ --- (1)

Let us determine the nature of roots:

Here in $x^{2}-2 x+5=0$ a = 1 ; b = -2 ; c = 5

$b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16$

Since $b^2 - 4ac < 0$ , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

$x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}$

On solving we get,

$x=\frac{2 \pm \sqrt{4-20}}{2}$

$x=\frac{2 \pm \sqrt{-16}}{2}$

$x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}$

we know that square root of -1 is "i" which is a complex number

$\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}$

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0

3 years ago