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grin007 [14]
3 years ago
9

What is the area of a table with a lenth of 7 feet and a width of 9 feet?

Mathematics
2 answers:
DanielleElmas [232]3 years ago
8 0
The answer would be 63
Vitek1552 [10]3 years ago
5 0
It would be an area of 63 feet
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Solve for x in 4x-4/x+4=10
Amiraneli [1.4K]

Answer:

-22/3 =x

Step-by-step explanation:

(4x-4) /(x+4) = 10

Multiply each side by (x+4)

(4x-4) /(x+4) * (x+4) = 10 * (x+4)

(4x-4) = 10 * (x+4)

Distribute

4x-4 = 10x+40

Subtract 4x from each side

4x-4-4x = 10-4x+40

-4 = 6x+40

subtract 40 from each side

-4 -40 = 6x+40-40

-44 = 6x

Divide each side by 6

-44/6 = -6x/6

-22/3 =x

4 0
3 years ago
Solve the system by substitution​
Alexxandr [17]
1) Solve one of the equations for either variable.

2) Substitute the expression from Step 1 into the other equation.

3) Solve the resulting equation.

4) Substitute the solution in Step 3 into one of the original equations to find the other variable.

5) Write the solution as an ordered pair.
5 0
2 years ago
Suppose that an automobile manufacturer designed a radically new lightweight engine and wants to recommend the grade of gasoline
yawa3891 [41]

Answer:

B) 4.07

Step-by-step explanation:

First we need to calculate the mean of all the data, which is the same as the mean of the means of each grade of gasoline:

Regular    BelowRegular   Premium   SuperPremium

39.31             36.69                38.99             40.04

39.87            40.00                40.02             39.89

39.87            41.01                  39.99             39.93

X1⁻=39.68    X2⁻= 39.23       X3⁻= 39.66    X4⁻=  39.95

Xgrand⁻ = (39.68+39.23+39.66+39.95)/4 = 39.63

Next we need to calculate the sum of squares within the group (SSW) and the sum of squares between the groups (SSB), and the respective degrees of freedom):

SSW = [ (39.31-39.68)² + (39.87-39.68)² + (39.87-39.68)² ] + [ (36.69-39.23)² + (40.00-39.23)² + (41.01-39.23)² ] + [ (38.99-39.66)² + (40.02-39.66)² + (39.99-39.66)² ] + [ (40.04-39.95)² + (39.89-39.95)² + (39.93-39.95)² ] = [0.2091] + [10.2129] + [0.6874] + [0.0121] = 11.12

SSW =  11.12

Degrees of freedom in this case is calculated by m(n-1), with m being the number of grades of gasoline (4) and n being the number of trial results for each one (3), so we would have 4(3-1) = 8 degrees of freedom

SSB = [ (39.68-39.63)² + (39.68-39.63)² + (39.68-39.63)²] + [ (39.23-39.63)² + (39.23-39.63)² + (39.23-39.63)² ] + [ (39.66-39.63)² + (39.66-39.63)² + (39.66-39.63)² ] + [ (39.95-39.63)² + (39.95-39.63)² +(39.95-39.63)² ] = [0.0075] + [0.48] + [0.0027] + [0.3072] = 0.7974

SSB =  0.80

For this case, the degrees of freedom are m-1, so we would have 4-1 = 3 degrees of freedom

Now we can establish the hypothesis for the test:

H0: μ1 = μ2 = μ3 = μ4

The null hypothesis states that the means of miles per gallon for each fuel are the same, indicating that the drade of gasoline does not make a difference, therefore our alternative hypothesis will be:

H1: the grade of gasoline does makes a difference

We will use the F statistic to test the hypothesis, which is calculated like follows:

F - statistic = (SSB/m-1) / (SSW/m(n-1)) = (0.80/3) / (11.12/8) = 0.19

We know that the level of significance we are using is α = 0.05, so to find the critical value F we need to look at some table of critical values for the F distribution for the 0.05 significance level (like the attached image). Then we just need to look fot the value that is located in the intersection between the degrees of freedom we have in the numerator (horizontal) and the denominator (vertical) of the statistic (3 and 8). That critical value is:

Fc = 4.07

3 0
3 years ago
1kg= 2.2 pounds<br> Change 44 pounds in kg
Lyrx [107]
<u><em>Answer:</em></u>
44 pounds = 20 kg

<u><em>Explanation:</em></u>
<u>We are given that:</u>
1 kg = 2.2 pounds

To convert 44 pounds into kg, all we have to do is <u>cross multiplication</u> as follows:
1 kg .................> 2.2 pounds
?? kg .................> 44 pounds

<u>Now, we solve as follows:</u>
4 kg = \frac{44*1}{2.2} = 20 pounds

Hope this helps :)
4 0
3 years ago
Niki makes the same payment every two months to pay off his $61,600 loan. The loan has an interest rate of 9.84%, compounded eve
Alenkasestr [34]
The question is an annuity question with the present value of the annuity given.
The present value of an annuity is given by PV = P(1 - (1 + r/t)^-nt) / (r/t) where PV = $61,600; r = interest rate = 9.84% = 0.0984; t = number of payments in a year = 6; n = number of years = 11 years and P is the periodic payment.
61600 = P(1 - (1 + 0.0984/6)^-(11 x 6)) / (0.0984 / 6)
61600 = P(1 - (1 + 0.0164)^-66) / 0.0164
61600 x 0.0164 = P(1 - (1.0164)^-66)
1010.24 = P(1 - 0.341769) = 0.658231P
P = 1010.24 / 0.658231 = 1534.78
Thus, Niki pays $1,534.78 every two months for eleven years.
The total payment made by Niki = 11 x 6 x 1,534.78 = $101,295.48
Therefore, interest paid by Niki = $101,295.48 - $61,600 = $39,695.48
8 0
3 years ago
Read 2 more answers
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