3 years ago

Subtract. (9x2+3x+6)–(8x2+3)

Mathematics

1 answer:

max2010maxim [7]3 years ago

3 0

Answer:

x^2 +3x +3

Step-by-step explanation:

(9x^2+3x+6)–(8x^2+3)

Distribute the negative sign

(9x^2+3x+6)–8x^2-3

Combine like terms

9x^2–8x^2+3x+6–8x^2-3

x^2 +3x +3

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U = 6i – 10j<br> g= -81 – 11j<br> Find: -3u + 5g

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Answer:

$-3u + 5g =-58i -25j$

Step-by-step explanation:

Given

$u = 6i - 10j$

$g=-8i - 11j$

Required

$-3u + 5g$

We have:

$-3u + 5g$

This gives:

$-3u + 5g = -3(6i - 10j) + 5(-8i - 11j)$

Open bracket

$-3u + 5g = -18i + 30j - 40i - 55j$

Collect like terms

$-3u + 5g = -18i - 40i+ 30j - 55j$

$-3u + 5g =-58i -25j$

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