What are ways do you use math.How would the day have been different if you couldn't do math.

1 answer:

8 0

Will when you buy things and you don't know how to do math people can rip you off by charging you a high percentage of tax or by giving you less change

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What is the length of line segment A.B?<br> Please help!!

weqwewe [10]

Answer:

x = 6.40 units

Step-by-step explanation:

4^2 + 5^2 = x^2

x = 6.40 units

5 0

3 years ago

F(x) = -2x, g(x)= -2x-1

GarryVolchara [31]

Answer:

I graphed the two points on a graph in the attachment! Hope this helps! :)

Step-by-step explanation:

4 0

3 years ago

Groan needs to buy some pencils. Brand A has a pack of 24 pencils for 8.77 .brand B has a pack of 26 pencils for $9.84 find the

ratelena [41]

Brand A has a unit price of .37 cents
brand B has a unit price of .38 cents
so you get 2 more pencils for .1 cent each, so brand B is the better deal

3 0

3 years ago

Read 2 more answers

5th grade math. correct answer will be marked brainliest, answer the blank one!!

Likurg_2 [28]

If mike runs 3 3/4 miles each day 6 1/2 days a week the answer would be 10.0

8 0

3 years ago

Place (dlick and drag) one option from each of the lists below Into Its corresponding box to

earnstyle [38]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

$y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{3}}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-1}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-1}\implies 3}}$

so we're really looking for the equation of a line whose slope is 3 and passes through (1 , 10)

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{10})\qquad \qquad \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{3}(x-\stackrel{x_1}{1}) \\\\\\ y-10=3x-3\implies y=3x+7$

5 0

2 years ago