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koban [17]
3 years ago
13

Find the number of terms and the degree of this polynomial -3p^8+2p^2-5

Mathematics
1 answer:
Hoochie [10]3 years ago
3 0

Answer:

The degree if the polynomial is 8.

Step-by-step explanation:

When the polynomial is of the form ax^n+bx^(n-1)+.........+c, then n is the degree of the polynomial which in this case is 8.

as the given polynomial has three terms so it is trinomial.

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What are the dimensions of the base of the pyramid?
inn [45]

Answer:

I don’t understand the question

Step-by-step explanation:

4 0
3 years ago
The length l, width w, and height h of a box change with time. At a certain instant the dimensions are l = 3 m and w = h = 6 m,
Gemiola [76]

Answer:

a) The rate of change associated with the volume of the box is 54 cubic meters per second, b) The rate of change associated with the surface area of the box is 18 square meters per second, c) The rate of change of the length of the diagonal is -1 meters per second.

Step-by-step explanation:

a) Given that box is a parallelepiped, the volume of the parallelepiped, measured in cubic meters, is represented by this formula:

V = w \cdot h \cdot l

Where:

w - Width, measured in meters.

h - Height, measured in meters.

l - Length, measured in meters.

The rate of change in the volume of the box, measured in cubic meters per second, is deducted by deriving the volume function in terms of time:

\dot V = h\cdot l \cdot \dot w + w\cdot l \cdot \dot h + w\cdot h \cdot \dot l

Where \dot w, \dot h and \dot l are the rates of change related to the width, height and length, measured in meters per second.

Given that w = 6\,m, h = 6\,m, l = 3\,m, \dot w =3\,\frac{m}{s}, \dot h = -6\,\frac{m}{s} and \dot l = 3\,\frac{m}{s}, the rate of change in the volume of the box is:

\dot V = (6\,m)\cdot (3\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot (3\,m)\cdot \left(-6\,\frac{m}{s} \right)+(6\,m)\cdot (6\,m)\cdot \left(3\,\frac{m}{s}\right)

\dot V = 54\,\frac{m^{3}}{s}

The rate of change associated with the volume of the box is 54 cubic meters per second.

b) The surface area of the parallelepiped, measured in square meters, is represented by this model:

A_{s} = 2\cdot (w\cdot l + l\cdot h + w\cdot h)

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time:

\dot A_{s} = 2\cdot (l+h)\cdot \dot w + 2\cdot (w+h)\cdot \dot l + 2\cdot (w+l)\cdot \dot h

Given that w = 6\,m, h = 6\,m, l = 3\,m, \dot w =3\,\frac{m}{s}, \dot h = -6\,\frac{m}{s} and \dot l = 3\,\frac{m}{s}, the rate of change in the surface area of the box is:

\dot A_{s} = 2\cdot (6\,m + 3\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m+6\,m)\cdot \left(3\,\frac{m}{s} \right) + 2\cdot (6\,m + 3\,m)\cdot \left(-6\,\frac{m}{s} \right)

\dot A_{s} = 18\,\frac{m^{2}}{s}

The rate of change associated with the surface area of the box is 18 square meters per second.

c) The length of the diagonal, measured in meters, is represented by the following Pythagorean identity:

r^{2} = w^{2}+h^{2}+l^{2}

The rate of change in the surface area of the box, measured in square meters per second, is deducted by deriving the surface area function in terms of time before simplification:

2\cdot r \cdot \dot r = 2\cdot w \cdot \dot w + 2\cdot h \cdot \dot h + 2\cdot l \cdot \dot l

r\cdot \dot r = w\cdot \dot w + h\cdot \dot h + l\cdot \dot l

\dot r = \frac{w\cdot \dot w + h \cdot \dot h + l \cdot \dot l}{\sqrt{w^{2}+h^{2}+l^{2}}}

Given that w = 6\,m, h = 6\,m, l = 3\,m, \dot w =3\,\frac{m}{s}, \dot h = -6\,\frac{m}{s} and \dot l = 3\,\frac{m}{s}, the rate of change in the length of the diagonal of the box is:

\dot r = \frac{(6\,m)\cdot \left(3\,\frac{m}{s} \right)+(6\,m)\cdot \left(-6\,\frac{m}{s} \right)+(3\,m)\cdot \left(3\,\frac{m}{s} \right)}{\sqrt{(6\,m)^{2}+(6\,m)^{2}+(3\,m)^{2}}}

\dot r = -1\,\frac{m}{s}

The rate of change of the length of the diagonal is -1 meters per second.

6 0
3 years ago
Please help me I do not get this!! Thanks
Solnce55 [7]
The answer is C. Hope you get it!
7 0
3 years ago
Read 2 more answers
A lawn company advertises that they can spread 7,500 square feet of grass seed in 2 1/2
den301095 [7]
If you would like to know the number of square feet of grass seeds that the lawn company can spread per hour, you can calculate this using the following steps:

7500 square feet ... 2 1/2 hours = 5/2 hours
x square feet = ? ... 1 hour

7500 * 1 = 5/2 * x
7500 = 5/2 * x       /*2/5
x = 7500 * 2 / 5
x = 3000 square feet

The correct result would be 3000 square feet.
7 0
2 years ago
Read 2 more answers
Which point is on the graph of the equation y = 4x - 3?
Mandarinka [93]

Answer:

D. (2, 5)

Step-by-step explanation:

In order to determine whether an ordered pair is on the graph of a given equation, when we plug the x-coordinate in for x and the y-coordinate in for y, the equation should hold true.

Let's try each of the answer choices:

A. (4, -3)

y = 4x - 3

-3 =? 4 * 4 - 3

-3 =? 16 - 3

-3 =? 13

This is clearly wrong, so eliminate A.

B. (3, 4)

y = 4x - 3

4 =? 4 * 3 - 3

4 =? 12 - 3

4 =? 9

This is clearly wrong, so eliminate B.

C. (1, -1)

y = 4x - 3

-1 =? 4 * 1 - 3

-1 =? 4 - 3

-1 =? 1

This is clearly wrong, so eliminate C.

D. (2, 5)

y = 4x - 3

5 =? 4 * 2 - 3

5 =? 8 - 3

5 =? 5

This is true, so D is the answer.

Our answer is thus D.

<em>~ an aesthetics lover</em>

7 0
3 years ago
Read 2 more answers
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