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sineoko [7]
3 years ago
12

48

Mathematics
1 answer:
kirill115 [55]3 years ago
7 0
The answer is 3 I took a test with this question your welcome
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If ⅓y = 9; then y =?​
Svetach [21]

<u>Answer:</u>

<h2>y = 27</h2>

<u>Eexplanation:</u>

1/3y = 9

y/3 = 9

y = 9 × 3

y = 27

4 0
2 years ago
Read 2 more answers
Write each fraction as a percent.<br><br> 1. 3/10<br><br> 2. 7/20<br><br> 3. 8/25
allsm [11]
3/10=30/100=30%
7/20=35/100=35%
8/25=32/100=32%
4 0
3 years ago
Read 2 more answers
For the rhombus below, find the measure of angles 1,2,3 and 4.
Alexus [3.1K]

Answer:

∠1 is 33°

∠2 is 57°

∠3 is 57°

∠4 is 33°

Step-by-step explanation:

First off, we already know that ∠2 is 57° because of alternate interior angles.

Second, it's important to know that rhombus' diagonals bisect each other; meaning they form 90° angles in the intersection. Another cool thing is that the diagonals bisect the existing angles in the rhombus. Therefore, 57° is just half of something.

Then, you basically just do some other pain-in-the-butt things after.

Since that ∠2 is just the bisected half from one existing angle, that means that ∠3 is just the other half; meaning that ∠3 is 57°, as well.

Next is to just find the missing angle ∠1. Since we already know ∠3 is 57°, we can just add that to the 90° that the diagonals formed at the intersection.

57° + 90° = 147°

180° - 147° = 33°

∠1 is 33°

Finally, since that ∠4 is just an alternate interior angle of ∠1, ∠4 is 33°, too.

5 0
3 years ago
A state end-of-grade exam in American History is a multiple-choice test that has 50 questions with 4 answer choices for each que
Assoli18 [71]

Answer:

Q1) The student has a 0.01% probability of passing the test.

Q2) She has a 99.91% probability of passing in the test.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he gets it correct, or he gets it wrong. So we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

For this problem, we have that:

Question 1.

There are 50 questions, so n = 50.

The student is going to guess each question, so he has a \pi = \frac{1}{4} = 0.25 probability of getting it right.

He needs to get at least 25 question right.

So we need to find P(X \geq 25).

Using a binomial probability calculator, with n = 50 and \pi = 0.25 we get that P(X \geq 25) = 0.0001.

This means that the student has a 0.01% probability of passing the test.

Question 2.

Now, we need to find P(X \geq 25) with \pi = 0.70. So P(X \geq 25) = 0.9991

She has a 99.91% probability of passing in the test.

7 0
3 years ago
Read 2 more answers
Mr. Watson uses 10.5 gallons of gasoline to drive the first 313 miles of the trip. How many gallons of gasoline would he need to
adelina 88 [10]
450/313*10.5 = 15.09.... which is approx is 15
7 0
3 years ago
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