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Vesna [10]
3 years ago
11

Determine the equation of the line that passes through the given points. (If you have a graphing calculator, you can use the tab

le feature to confirm that the coordinates of both points satisfy your equation.) (3.5, 8.2) and (2, 7.3) a. y = -0.6x - 6.1 b. y = 0.6%-6.1 C. y=-0.6x + 6.1 d. y = 0.6x + 6.1 Please select the best answer from the choices provided A B C D​
Mathematics
2 answers:
svetlana [45]3 years ago
8 0

Answer:

Its c i did it

Step-by-step explanation:

MAXImum [283]3 years ago
8 0

Answer:

I think it is C

Step-by-step explanation:

Hope this helped have an amazing day!

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The functions q and r are defined as follows.
UkoKoshka [18]
Q(3) = -2(3)+2 = -4
r(q(3)) = (-4)^2-1 = 15
3 0
3 years ago
Let (12,-5) be a point on the terminal side of an angle 0. Find the values of sin e, cose, and tan
lord [1]

Answer:

Sin = -5/13

Cos = 12/13

Tan = -5/12

Step-by-step explanation:

5 0
3 years ago
Super Salad Dressing is made with 8 mL of oil for every 3 mL of vinegar. Which mixtures will taste the same as Super Salad Dress
sesenic [268]

Answer: The Answers Are: A, C, E

Step-by-step explanation: Find the Equivalent Ratios! :)

8 0
4 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
Bananas cost $0.54 per lb and grapes cost$1.28 per lb. Leanne bought 2.6 lb of bananas and 3.1 lb of grapes .How much did she pa
slamgirl [31]
So all u have to do is just add $1.28 and $0.54
5 0
3 years ago
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