Using the Heron's formula, the area of the triangle is: D. 95 square inches.
<h3>What is the Heron's Formula?</h3>
Area = √[s(s - a)(s - b)(s - c)] where s is half the perimeter, or (a + b + c)/2.
Given the following:
s = semi-perimeter = 1/2(50) = 25 in.
a = length of side a = 22 in.
b = length of side b = 13 in.
c = length of side c = 50 - 22 - 13 = 15 in.
Plug in the values
Area = √[25(25 - 22)(25 - 13)(25 - 15)]
Area = √[25(3)(12)(10)]
Area ≈ 95 square inches.
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Answer:
there is no solution to it as the equation isn't true (It doesn't make sense)
Step-by-step explanation:
if they paid $78 each for every uniform then each uniform would be $78
9514 1404 393
Answer:
a) 5 cm
b) 8 cm
c) 9 m
Step-by-step explanation:
It can be worthwhile to work the last attachment (a) first, since these are all variations of the same triangle.
The Pythagorean theorem tells you the sum of the squares of the legs is the square of the hypotenuse.
<u>Problem 6a</u>:
3² +4² = x² . . . . fill in the given numbers; all measures in cm
9 + 16 = x² . . . . simplify exponents
25 = x² . . . . . . . simplify sum
x = √25 = 5 . . . take the square root.
x = 5 cm . . . . . . apply units
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Note that this triangle is a 3-4-5 right triangle. That is a set of side lengths (ratios) that is useful to remember. In this problem set, you see it again immediately.
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<u>Problem 6b</u>:
Shortest-to-longest, the side ratios of the given triangle are ...
6 : x : 10
For some x', this is ...
3 : x' : 5 . . . . . . . . . . . . . matches a 3-4-5 triangle with x' = 4
The scale factor is 6/3 = 10/5 = 2, so we have ...
x = 2·x' = 2·4 = 8
x = 8 cm . . . . . with units
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<u>Problem 6c</u>:
The side ratios are ...
x : 12 : 15 which reduces to x' : 4 : 5
This matches a 3-4-5 triangle with x' = 3, and a scale factor of 12/4 = 15/5 = 3.
Then ...
x = 3·x' = 3·3 = 9
x = 9 m . . . . . with units
Negative rational number that is not an integer
