Complete question is;
Kamal said the distance from the top of the balloon to the ground in the Example image attached is √353 ft. What mistake might Kamal have made?
Answer:
the mistake Kamal made is that she probably used 17 ft as the perpendicular side of the triangle with b as the hypotenuse instead of using 17ft as the hypotenuse
Explanation:
From the image attached, we can see that the distance from the top of the balloon which is blue in color to the ground is denoted by "b".
Now the triangle is a right angle triangle with hypotenuse = 15ft + 2ft = 17 ft; the adjacent side = 8 ft, while the opposite side is "b".
Thus, we can use pythagoras theorem to solve this as;
b = √(17² - 8²)
b = √(289 - 64)
b = √225
b = 15ft
However,we are told Kamal got b as √353 ft.
From inspection of the calculations we just did, if we had used addition instead of subtraction, we would have gotten b = √353 ft.
Thus, we can under that the mistake Kamal made is that she probably used 17 ft as the perpendicular side of the triangle with b as the hypotenuse instead of using 17ft as the hypotenuse.
Answer:
170 N
Explanation:
Given in the question that, work a bulldozer can do = 4500 J
<h3>
Step 1</h3>
We will use trigonometry identity to find the distance bulldozer will travel up the hill
sin(35) = opp/hypo
sin(35) = 15/hypo
hypo = 15/sin(35)
hypo = 26.15m
<h3>Step 2</h3>
Formula to use
work done = force × distance
Plug values in the above formula
4500 = force x 26.15
force = 4500/26.15
force = 172.08
force ≈ 170 N
<h3 /><h3 /><h3 />
Answer:
v = 3.135 m/s
Explanation:
given,
mass of car = 2.1 x 10³ Kg
length of driveway = 5.1 m
angle on inclination, θ = 17°
frictional force, f = 4.0 ✕ 10³ N
The force from the newton's second law
The speed of the car
v = 3.135 m/s
Speed of the car at the bottom of the driveway, v = 3.135 m/s
B or c
It’s kinda confusing
Answer:
The elevator's velocity after 6 seconds is 3.189m/s
Explanation:
Using Newton's 2nd law:Fnet = ma
Mg - N = ma
Where m = mass
N = normal force
a = acceleration
g = acceleration due to gravity
Substituting the given values and finding acceleration
(95kg)(9.8m/s^2) - 830N = 95kg x a
a = (931 -830) / 95
a = 101/95
a = 1.063m/s^2
After 3 seconds, the weight 0f the person is equal to the actual weight of the person, thus the elevator will be moving at a constant velocity.
Using kinematic equation:
V = u + at
Where V = final velocity
U = initial velocity = 0
a = acceleration
t = time
V = 0 + 1.063 × 3
V = 3.189m/s
This velocity does not change . The elevator travels the test of the time at the same velocity. Therefore,the velocity at 6 seconds = 3.189m/s