Answer:
The Earth weighs about:
13,170,000,000,000,000,000,000,000 pounds
or
5.97 billion trillion metric tons
Explanation:
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#TheWizzer
Both the object and earth pulls each other towards itself but since the mass and pulling force of objects are very small the pulling force of objects are negligible.
Imagine an object is moving in one dimension on a number line, and for this we'll say that the numbers on the line are a metre apart. If the object moves from 2 m to 7 m, the change in position is 7-2=+5 metres. But if the object moves back from 7 m to 2 m, the change in position is 2-7=-5 metres. since

, and time is always positive, velocity will be positive in one direction and negative in the other direction.
Answer:
Choice a. Approximately
on average.
Explanation:
The electric current through a wire is the rate at which electric charge flows through a cross-section of this wire.
Assume that electric charge of size
flowed through a wire cross-section over a period of time
. The average current in that wire would be:
.
For this question:
, whereas
.
Therefore, the average current in this circuit would be:
.
However, the units in the choices are all in
(for Amperes.) One Ampere is equal to one
. It will take some unit conversations to change the unit of
(coulombs-per-minute) to coulombs-per-second.
.
Hence, the most accurate choice here would be choice a.
Answer:
Explanation:
charge on the capacitor = capacitance x potential
= 1.588 x 3.4
= 5.4 C
Energy of capacitor = 1 / 2 C V ² , C is capacitance , V is potential
= .5 x 3.4 x 1.588²
= 4.29 J
If I be maximum current
energy of inductor = 1/2 L I² , L is inductance of inductor .
energy of inductance = Energy of capacitor
1/2 L I² = 4.29
I² = 107.25
I = 10.35 A
Time period of oscillation
T = 2π √ LC
=2π √ .08 X 3.4
= 3.275 s
current in the inductor will be maximum in T / 4 time
= 3.275 / 4
= .819 s.
Total energy of the system
= initial energy of the capacitor
= 4.29 J