Answer:
1) k = 52 N/m
2) E = 1.0 J
3) ω = 8.1 rad/s
4) v = 1.4 m/s
Though asked for a velocity, we can only supply magnitude (speed) because we don't have enough information to determine direction.
If it happens to be the first time it is at y = - 10 cm after release, the velocity is upward.
Explanation:
Assuming the initial setup is after all transients are eliminated.
kx = mg
k = mg/x = 0.8(9.8) / 0.15
k = 52.26666.... ≈ 52 N/m
E = ½kA² = ½(52)(0.20²) = 1.045333... ≈ 1.0 J
ω = √(k/m) = √(52 / 0.8) = 8.0829... ≈ 8.1 rad/s
½mv² = ½kA² - ½kx²
v = √(k(A² - x²)/m) = √(52(0.20² - 0.10²)/0.8) = 1.39999... ≈ 1.4 m/s
<h3><u>Answer;</u></h3>
= 2868 Newtons
<h3><u>Explanation;</u></h3>
Centripetal force is a force that acts on an object or a body in circular path and is directed towards the center of the circular path.
Centripetal force is given by the formula;
mv²/r ; where m is the mass of the body, r is the radius of the circular path and v is the velocity of a body;
mass = 65 kg, velocity = 15 m/s and r = 5.1 m
Therefore;
Centripetal force = (65 × 15²)/ 5.10
= 2867.65 Newtons
= 2868 N
Answer:
49 m/s
Explanation:
Initial potential energy = final kinetic energy
PE = KE
mgh = ½ mv²
v = √(2gh)
v = √(2 × 10 m/s² × 120 m)
v = 49 m/s
Answer:
The point at which the electrical potential is zero is x = +0.33 m.
Explanation:
By definition the electrical potential is:
Where:
K: is Coulomb's constant = 9x10⁹ N*m²/C²
q: is the charge
r: is the distance
The point at which the electrical potential is zero can be calculated as follows:
(1)
q₁ is the first charge = +3 mC
r₁ is the distance from the point to the first charge
q₂ is the first charge = -6 mC
r₂ is the distance from the point to the second charge
By replacing r₁ = 1 - r₂ into equation (1) we have:
(2)
By solving equation (2) for r₂:
Therefore, the point at which the electrical potential is zero is x = +0.33 m.
I hope it helps you!
I couldnt type it out so here's a picture