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dimaraw [331]
3 years ago
6

Please I need an answer

Physics
2 answers:
eduard3 years ago
7 0
B or c
It’s kinda confusing
aliina [53]3 years ago
5 0

Answer:

D

Explanation:

The ballon will repel

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An Alaskan rescue plane traveling 39 m/s drops a package of emergency rations from a height of 198 m to a stranded party of expl
Elden [556K]

y = 0m

y0 = 166m

v0y = 0 m/s

g = 9.8 m/s^2

t = ?


Solve for t:

y = y0 + v0y*t - (0.5)gt^2

0 = 166 - (0.5)(9.8)t^2

t = 5.82 s


Now, using time, we can solve for the range using the equation:


x = vx(t)

x = (40)(5.82)

x = 232.8 m


The impact horizontal component of velocity will be 40 m/s as velocity in terms of x is always constant. To find the impact vertical component of velocity, we use the equation:


v = v0y - gt

v = 0 - (9.8)(5.82)

v = -57.04 m/s


3 0
4 years ago
Read 2 more answers
n a ballistics test, a potato gun shoots a 0.34 kg potato into a 5.0 kg catching cart. The cart recoils at 3.7 m/s after catchin
Gala2k [10]

The initial velocity of the potato is 54.41 m/s.

The given parameters:

  • <em>Mass of the potato, m = 0.34 kg</em>
  • <em>Mass of the cart, m = 5.0 kg </em>
  • <em>Velocity of the recoil, u₂ = 3.7 m/s</em>

<em />

The initial velocity of the potato is calculated by applying the principle of conservation of energy as follows;

m_1u_1 = m_2 u_2\\\\u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{5 \times 3.7}{0.34} \\\\u_1 = 54.41 \ m/s

Thus, the initial velocity of the potato is 54.41 m/s.

Learn more about conservation of linear momentum here: brainly.com/question/7538238

6 0
3 years ago
A plane takes off in san francisco at noon and flies toward the southeast. an hour later, it is 400 kilometers east and 300 kilo
eduard
This first step involves a right triangle. If the plane is 400 km east and 300 km south of the origin, and it flew in a straight line, then you can construct a right triangle with side lengths 300, 400, and c. You may recognize that these are multiples of the Pythagorean triple 3, 4, 5, so the side length c is 500 km. Otherwise, you would write 
c^2 = 300^2+400^2 \\ c = 500. 

This second step is, if I am correctly interpreting "degrees south of east," to find the angle formed by the horizontal line representing the east and the path of the plane. I made a diagram that does just that (see attached). You can use a trig function of one of the angles to solve. I chose
tan(C)= \frac{3}{4}  \\  arctan( \frac{3}{4})=36.870. Thus, I believe it is 37° south of east.

5 0
3 years ago
Inside the wall of a house, an L-shaped section of hot-water pipe consists of three parts: a straight, horizontal piece 28.0 cm
goblinko [34]

Answer:

The magnitude and direction are

7.638×10-4m

80.01°

Explanation:

We know that the coefficient of linear expansion for copper = 16.6×10^-6 m/m-C

ΔT = 40.2 - 18.0 = 28.5 C°

The expansion of horizontal pipe length can be calculated as

= (0.28)(16.6×10^-6)(28.5) = 13247×10^-8

= 0.0001325 m

The expansion of vertical pipe length = (1.28)(16.6×10^-6)(28.5) = 60557×10^-8 = 0.000752229 m

horizontal displacement = 0.1325 mm

= 1.356×10^-4m

vertical displacement = 0.75223mm

=7.5223×10-4m

size of total displacement can be calculated as

√(x²+y²)

Where x and y are vertical and horizontal displacement respectively

= √(0.1325)²+(0.75223)² =

= 0.7638 mm

= 7.638×10-4m

Angle below horizontal = arctan Θ

= 0.75223/0.1325

=5.6772

= arctan (5.6772)

= 80.01°

Therefore, the the magnitude and direction of the displacement of the pipe elbow when the water flow is turned at (7.638×10-4m) 0.7638 mm and 80.01°

7 0
3 years ago
A 26 kg body is moving through space in the positive direction of an x axis with a speed of 350 m/s when, due to an internal exp
Gnom [1K]

Answer:

a.) 1567.2 m/s

b.) 149.4 m/s

Explanation:

Given that a 26 kg body is moving through space in the positive direction of an x axis with a speed of 350 m/s when, due to an internal explosion, it breaks into three parts. One part, with a mass of 7.8 kg, moves away from the point of explosion with a speed of 180 m/s in the positive y direction. A second part, with a mass of 8.8 kg, moves in the negative x direction with a speed of 640 m/s.

The x-component of the third part can be calculated by assuming that it moves in a positive x axis.

The third mass = 26 - ( 7.8 + 8.8)

The third mass = 26 - 16.6

The third mass = 9.4kg

since momentum is conserved, the momentum before explosion will be equal to sum of the momentum after explosion

26 x 350 = -8.8 x 640 + 9.4V

9100 = -5632 + 9.4V

9.4V = 9100 + 5632

9.4V = 14732

V = 14732/9.4

V = 1567.2 m/s

(b) y-component of the velocity of the third part will be

7.8 x 180 = 9.4 V

1404 = 9.4V

V = 1404/9.4

V = 149.4 m/s

7 0
3 years ago
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