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mr_godi [17]
4 years ago
10

Your statement balance is $200.36. You have an outstanding check for $112.56 and an outstanding deposit for $68.34. What is your

adjustment balance?
A.) $19.46
B.) $156.14
C.) $244.58
D.) $381.26
Mathematics
1 answer:
adoni [48]4 years ago
8 0

Answer:

c

Step-by-step explanation:

200.36-112.56=87.8

87.8+68.34= 156.14

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David and Jillian are playing a boardgame together Jillian wants to trade her wool cards for David ore cards the double number l
Cloud [144]

Answer:

Step-by-step explanation:

Given that:

Jillian is willing to trade her wool cards for David ore cards

The double number line indicates that:

David will trade three ore cards to Jillian for six wool cards;

Based on the ratio, we have:

= \dfrac{6}{3}

= 2

Thus, the number of wool Jillian would need to trade for 1 ore card will be

= 1 × 2

= 2

For 2 ore card

= 2 × 2

= 4

For 3 ore card

= 3  × 2

= 6

The number of wool Jillian would need to trade for 4 ore card will be

= 4 × 2

= 8

5 0
3 years ago
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Seed mix a is more expensive than b
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3 years ago
PLEASE HELP THANKS, Scale factoring
Radda [10]

Answer:

17.5 or 35

Step-by-step explanation:

because 350/10=35

350/12=17.5

8 0
3 years ago
). If a, ß are zeroes of the quadratic polynomial p(x)=kx²+4x+4 such
natta225 [31]

Answer:

The values of k are 2/3 and -1

Step-by-step explanation:

Product of zeros = αβ= constant  / coefficient of x^2 =  4/k

Sum of zeros =α+β = - coefficient of x / coefficient of x^2= -4/k

Given

Consider a= α and b= β

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(\alpha)^2 + (\beta)^2 can be written as (\alpha)^2 + 2(\alpha)(\beta) + (\beta)^2 if we add \pm 2 (\alpha)(\beta) in the above equation.

(\alpha)^2 + 2(\alpha)(\beta) + (\beta)^2 -2(\alpha)(\beta)

(\alpha + \beta)^2 -2(\alpha)(\beta)

Putting values of αβ and α+β

(\frac {-4}{k})^2 -2( \frac {4}{k}) = 24\\\frac {16}{k^2} - \frac {8}{k} = 24\\Multiplying\,\, the \,\, equation\,\, with\,\, 8K^2\\ 2 - k= 3K^2\\3k^2-2+k=0\\or\\3k^2+k-2=0\\3k^2+3k-2k-2=0\\3k(k+1)-2(k+1)=0\\(3k-2)(k+1)=0\\3k-2=0 \,\,and\,\, k+1 =0\\k= 2/3 \,\,and\,\, k=-1

The values of k are 2/3 and -1

8 0
4 years ago
Display the set of data in a histogram.
VARVARA [1.3K]

Answer:

The answer to your question is the third histogram

Step-by-step explanation:

What we must check in a histogram is that the x-axis is represented the intervals and in the y-axis is represented the frequency.

The first histogram is incorrect just by observing the first bar, we notice that the correct frequency from 0 to 4 is 3, not 14. This histogram is incorrect.

Also, the second histogram is incorrect, the frequency of the first category is 3, not 12. This histogram is wrong.

The third histogram is correct because all the bars are in agreement with their frequencies.

The last histogram is incorrect, for example, the last frequency is 12, not 3.

4 0
3 years ago
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