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2 years ago

What value of n makes the statement true? 6xn · 4x2 = 24x6 n =

Mathematics

2 answers:

Degger [83]2 years ago

8 0

Answer:

Step-by-step explanation:

Hello,

$6\times x^n\times 4x^2=24x^{n+2}=24x^6\\\\x^{n+2}=x^6\\\\ n+2=6\\\\ n = 6-2=4\\\\ \\\large \boxed{\sf \bf n=4}$

Thank you

Luda [366]2 years ago

6 0

Answer:

N= 4

Step-by-step explanation:

on edge 2020

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A dose of medicine is made by diluting one part of concentrate to 5 parts of water. How much of the concentrate should there be

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3 years ago

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2 years ago

Read 2 more answers

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

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1 year ago