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Advocard [28]
3 years ago
10

7,278 to the nearest hundred

Mathematics
2 answers:
Vikentia [17]3 years ago
4 0

Answer:

7,300

Step-by-step explanation:

IrinaVladis [17]3 years ago
3 0

Answer:

7,300

Step-by-step explanation:

If the number in the tenths place is 5+, you add one to the number in the hundredths place and replace all the numbers after it with 0. If the number in the tenths place is below 5, keep the number in the hundredths place the same and replace all the numbers after it with 0.

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True or false, A function is a relation if and only if the x-values do not repeat in a given set
salantis [7]
Its false because it can't repeat in a set.
5 0
3 years ago
Read 2 more answers
(24x4) x19= 4(24xk)​
maksim [4K]

Answer:

Step-by-step explanation:

Hi there!

Simplify,

24.4.19 = 4.24.k

19=k

Have a nice day.

7 0
3 years ago
Please Help!!
leva [86]

Answer:

0.0069

Step-by-step explanation:

This is a power series problem.

The taylor power series expansion for sin(x) = x - x³/3! + (x^(5))/5! - (x^(7))/7! + (x^(9))/9! .......

Our question says we should use the first 5 terms to find the value of sin(π). Thus;

sin(π) = π - π³/3! + (π^(5))/5! - (π^(7))/7! + (π^(9))/9!

This gives;

π - (π^(3)/6) + (π^(5))/120 - (π^(7))/5040 + (π^(9))/362880 ≈ 0.0069

5 0
3 years ago
Two planes intersect at a...<br> A. Plane<br> B. Power<br> C. Point<br> D. Line
Anna71 [15]

Answer:

D. Line

Step-by-step explanation:

7 0
3 years ago
Why is it necessary to use the absolute value of the difference when finding the distance on a number line, but not necessary wh
padilas [110]
Remember that the distance on a number line is given by the formula: d=|x_{2}-x_{1}|
where 
d is the distance between the points. 
x_{2} is the second point in the number line.  
x_{1} is the first point in the number line.
Now, suppose we are trying to find the distance between the points -1 and -5; our first point is -1, so x_{1}=-1, and our second point is -5, so x_{2}=-5. Suppose we are going to find the distance between the two point without using absolute value:
d=x_{2}-x_{1}
d=-5-(-1)
d=-5+1
d=-4
Look what we have here, a negative distance! Since distances cannot be negative, we must use absolute value to always get postie distances between two point on a umber line:
d=|x_{2}-x_{1}|
d=|-5-(-1)|
d=|-5+1|
d=|-4|
d=4 

Now, the distance between two coordinates on a plane is given by the formula: d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}
where
d is the distance between the two coordinates
(x_{1},y_{2}) are the coordinates of the first point
(x_{2},y_{2}) are the coordinates of the second point 
Notice that (x_{2}-x_{1})^2 and (y_{2}-y_{1})^2 are squared, so it doesn't matter if we get a negative distance because a negative number raised to an even power (like 2) is always positive; therefore we don't need absolute value in this case because we won't ever get a negative distance. 


7 0
3 years ago
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