Answer:
The frequency of sound wave created by trumpet is 437.5Hz
Explanation:
Given
the speed of sound wave = 350 m
the wavelength of sound wave = 0.8 m
the frequency of sound wave = ?
All the waves have same relationship among wavelength, frequency and speed, which is given by the equation:
v = fλ, where
v is speed of the wave
f is frequency of the wave
λ is wavelength of the wave
therefore frequency of sound wave is given by
f = v/λ
= 350m/0.8m
= 437.5
= 437.5Hz (since 1 = 1 Hz (Hertz)
Hence the frequency of sound wave created by trumpet is 437.5Hz
Electricity and magnetism can be considered as part of the same phenomenon because both are generated by electromagnetic forces.
<h3>What is electricity?</h3>
Electricity is the movement or flow of negatively charged electrons through a suitable conductor where a charge is applied.
Moreover, magnetism is a natural phenomenon caused by the generation/movement of electric charges.
In conclusion, electricity and magnetism can be considered as part of the same phenomenon because both are generated by electromagnetic forces.
Learn more on electricity and magnetism here:
brainly.com/question/25144822
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Answer:
(A) 7.9 m/s^{2}
(B) 19 m/s
(C) 91 m
Explanation:
initial velocity (U) = 0 mph = 0 m/s
final velocity (V) = 85 mph = 85 x 0.447 = 38 m/s
initial time (ti) = 0 s
final time (t) = 4.8 s
(A) acceleration = 
= 
= 7.9 m/s^{2}
(B) average velocity = 
=
= 19 m/s
(C) distance travelled (S) = ut + 
= (0 x 4.8) + 
= 91 m
Answer:
a) Height of the antenna (in m) for a radio station broadcasting at 604 kHz = 124.17 m
b)Height of the antenna (in m) for radio stations broadcasting at 1,710 kHz =43.86 m
Explanation:
(a) Radiowave wavelength= λ = c/f
As we know, Radiowave speed in the air = c = 3 x 10^8 m/s
f = frequency = 604 kHz = 604 x 10^3 Hz
Hence, wavelength = (3x10^8/604x10^3) m
λ
= 496.69 m
So the height of the antenna BROADCASTING AT 604 kHz = λ /4 = (496.69/4) m
= 124.17 m
(b) As we know , f = 1710 kHz = 1710 x 10^3 Hz (1kHZ = 1000 Hz)
Hence, wavelength = λ = (3 x 10^8/1710 x 10^3) m
λ= 175.44 m
So, height of the antenna = λ /4 = (175.44/4) m
= 43.86 m
Answer:
Magnitude of gravitational force of the electron= 3.74×10^12N
Explanation:
Felectron= Fgravitational
Therefore:
Felectron/Fgravitational = kq^2/r^2 ×(r^2/Gm^2)
= kq^2/Gm^2
Where G= gravitational constant
m = mass of electron=9.1×10^-31
K= 8.9x10^9
q= 1.6×10^-19
Magnitude of gravitational force= (8.9×10^9)×(1.6×10^-19)^2/(6.7×10^-11)×(9.1×10^-31)
=( 2.2784×10^-28) / ( 6.097×10^-41)
= 3.74×10^12N
