Answer:
Explanation:
Given:
the displacement as the function of time:
here time is in seconds and the displacement in meters.
Now we differentiate this eq. of displacement to get the equation of velocity:
According to given the velocity is at some time:
& is the only time for (t>=0) instances when the particle will have a velocity of but in the opposite direction.
The outward push of the core created by nuclear fusion and the inward pull of gravity from the core
Answer:
Velocity of Afrom B=21m/s
Acceleration of A from B=1.68m/s°2
Explanation:
Given
Radius r=150m
Velocity of a Va= 54km/hr
Va=54*1000/3600=15m/s
Velocity of b Vb=82km/hr
VB=81*1000/3600=22.5mls
The velocity of Car A as observed from B is VBA
VB= VA+VBA
Resolving the vector into X and Y components
For X component= 15cos60=7.5m/s
Y component=22 5sin60=19.48m/s
VBA= √(X^2+Y^2)
VBA= ✓(7.5^2+19.48^2)=21m/s
For acceleration of A observed from B
A=VA^2/r= 15^2/150=1.5m/s
Resolving into Xcomponent=1.5cos60=0.75m/s
Y component=3cos60=1.5
Acceleration BA=√(0.75^2+1.5^2)
1.68m/s
Answer:
f = 6.66 cm
Explanation:
For this exercise we will use the constructor equation
1 / f = 1 / p + 1 / q
where f is the focal length, p is the distance to the object and q is the distance to the image
the expression for magnification is
m = h '/ h = - q / p
with this we have a system of two equations with two unknowns, in the problem they give us the distance to the image q = 10 cm and a magnification of m = -0.5
-0.5 = - q / p
p = - q / 0.5
p = - 10 / 0.5
p = 20 cm
now we can with the other equation look for the focal length
1 / f = 1/20 + 1/10
1 / f = 0.15
f = 6.66 cm
<span>Answer: 124eV
Explanation: Apply Planck - Einstein Relation to calculate the energy of an X-Ray photon that has a frequency of 3.00 x 10^16 Hz and the energy of a photon is proportional to its frequency
E= hv
where E - the energy of the photon
h - Planck's constant, equal to 6.626 x 10^-34 Js
v - the frequency of the photon
and 1 Hz is equal to 1 s^-1
Thus E= 1.988 x 10^-17J
Now convert the energy of photon from joules to eV
Therefore we get 1.988 x 10^-17J x ( 1 eV / 1.6022 x 10^-19 J)
= 124 eV.</span>