<h2>Answer:</h2><h2> b hopefully this helps you with work </h2>
Explanation:
F = MA
200 = 100 * A
A = 200/100
A = 2m/sec^2
<h3><em>hope </em><em>it </em><em>helps </em><em>you </em></h3>
1 in=2.54 cm=(2.54 cm)(1 m/100 cm)=0.0254 m
Therefore:
1 in=0.0254 m
1 in³=(0.0254 m)³=1.6387064 x 10⁻⁵ m³
Therefore:
8.06 in³=(8.06 in³)(1.6387064 x 10⁻⁵ m³ / 1 in³)≈1.321 x 10⁻⁴ m³.
Answer: 8.06 in³=1.321 x 10⁻⁴ m³
Speed v = initial speed u + acceleration a x time t
v=u+at = 2 + 4*3 = 14 m/s
The correct statements are:
B. a small rock sitting on top of a big rock
As the rock is at a height with respect to ground it has potential Energy
and
C. a stretched rubber band
A stretched rubber band has elastic potential energy
The others are actually moving and hence would consist of Kinetic energy. Potential energy is stored in objects that do not move and are stationary.
