Answer:
It will take both pumps 3.08 hours to fill the tank working together.
Explanation:
Pump A can fill the tank in 5 hours. Assuming that the pump gives out a steady flow of water, in one hour, pump A can fill 1/5th of the tank. Similarly, pump B in an hour, fills up 1/8th of the tank.
We must add up these two values, in order to find how much of the tank the two pumps can fill up together in one hour.
1/5 +1/8 =13/40
So 13/40 of the tank is filled in an hour. We need to find how many hours it will take for the entire tank to be filled. To do so, divide 40 by 13. This gives:
3.08 hours to fill up the tank.
Answer:
C 350W
Explanation:
Given power output to walk on a flat ground to be 300W, h = 0.05x, v = 1.4m/s
m = 70kg and g =9.8m/s².
x = horizontal distance covered
Total energy used = potential energy used in climbing and the energy used in a walking the horizontal distance.
E = mgh + 300t
Where t is the time taken to cover the distance
x = vt and h = 0.05vt
So
E = mg×0.05×vt + 300t
Substituting respective values
E = 70×9.8×0.05×1.4t +300t = 348t
P = E/t = 348W ≈ 350W.
Answer: W = 0.3853 J, e = 0.052 m
Explanation: Given that,
K =285.0N/M , L = 0.230m , F = 15N , e = ?
F = Ke
15 = 285 × e
e = 15÷ 285
e =0.052 m
e + L = 0.052 + 0.230
= 0.282m ( spring new length )
Work needed to stretch the spring
W = 1/2ke2
W = 1/2 × 285 x 0.052 × 0.052
W = 0.3853 J
Answer:
The density ρ of metal block is 8.92g/cm³
So from the given density table this corresponds to copper which has density of 8.92(g/mL)
Explanation:
Oh yeah, I got the correct unit update,
Now this problem bothers on the density of substances
We know that the density of a substance is expressed as
Density ρ= mass/ volume
Given data
Mass of metal block m= 62.44g
Volume of metal block v= 7 cm³
Hence we can find the density of the metal block by plugging in our data into the expression for density
ρ of metal block = 62.44/7
ρ of metal block = 8.92g/cm³
The block is a copper block
The average velocity is -4.17 m/s
Explanation:
The average velocity of a body is given by:

where
d is the displacement of the body
t is the time elapsed
For the student in this problem, we have:
Initial position: 
Final position: 
So the displacement is

The time elapsed is
t = 60 s
Therefore, the average velocity is

Where the negative sign means the student is moving towards the origin.
Learn more about average speed and velocity:
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