Answer:
So visible wavelength which is possible here is
416 nm and 693.3 nm
Explanation:
As we know that for normal incidence of light the path difference of the reflected ray is given as

so here we can say that for maximum intensity condition we will have

so we have

now for visible wavelength we have
for N = 1




for N = 2



for N = 3



I., II., and IV. are examples of acceleration. III. isn't.
Answer: The sum of an object's potential and kinetic energies is called the object's mechanical energy. As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy.
Answer:
Explanation:
The case relates to interference in thin films , in which we study interference of light waves reflected by upper and lower surface of a medium or glass.
For constructive interference , the condition is
2μt = ( 2n+1)λ/2
μ is refractive index of glass , t is thickness , λ is wavelength of light.
putting the given values
2 x 1.53 x 350 x 10⁻⁹ = ( 2n+1) λ/2
λ = 2142nm / ( 2n+1)
For n = 2
λ = 428 nm
This wave length will have constructive interference making this light brightest of all .
For n = 1
λ = 714 nm
So second largest brightness will belong to 700 nm wavelength.