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Andrei [34K]
3 years ago
8

The impact that an earthquake can have on an area?

Physics
2 answers:
tatyana61 [14]3 years ago
7 0

Answer:

The primary effects of earthquakes are ground shaking, ground rupture, landslides, tsunamis, and liquefaction. Fires are probably the single most important secondary effect of earthquakes.

Explanation:

Romashka-Z-Leto [24]3 years ago
6 0

Answer:

Some of the common impacts of earthquakes include structural damage to buildings, fires, damage to bridges and highways, initiation of slope failures, liquefaction, and tsunami. The types of impacts depend to a large degree on where the earthquake is located: whether it is predominantly urban or rural, densely or sparsely populated, highly developed or underdeveloped, and of course on the ability of the infrastructure to withstand shaking.

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How would life on earth be different if earth’s axis were not tilted with respect to its orbit?
Vladimir [108]

If Earth's axis was "straight up and down" instead of tilted, then ...

<span>-- There would be no seasons.

-- The climate at any one place would be the same all year around. 

-- The days would be the same length, everywhere,
    and all year around.

-- So would the nights.

-- The sun would be up a little more than 12 hours every day.
    It would be down a little less than 12 hours every day.

-- At the middle of the day, the sun would be at the same height
   in the sky all year around, not higher in some months and lower
   in others.

-- The equator would be the only place on Earth where the sun
    could ever be directly over your head.

-- If you were at the north pole or the south pole, the sun would be
   down on the horizon, and it would just go around and around you
   every day.  It would never rise or set, and it would never get any
   higher or lower.

</span>
4 0
3 years ago
Read 2 more answers
A 3 kg rock sits on a 0.8 meter ledge. If it is pushed off, how fast will it be going at the bottom?
andrey2020 [161]

As long as it sits on the shelf, its potential energy
relative to the floor is . . .

   Potential energy =      (mass) x (gravity) x (height) =

                                       (3 kg) x (9.8 m/s²) x (0.8m) = <u>23.52 joules</u> .

If it falls from the shelf and lands on the floor, then it has exactly that
same amount of energy when it hits the floor, only now the 23.52 joules
has changed to kinetic energy.

   Kinetic energy =                                          (1/2) x (mass) x (speed)²

                                                 23.52 joules = (1/2) x (3 kg) x (speed)²

Divide each side by  1.5 kg :     23.52 m²/s² = speed²

Take the square root of each side:    speed = √(23.52 m²/s²) =  <em>4.85 m/s </em> (rounded)


6 0
3 years ago
What is space time?​
Kay [80]
In physics, spacetime is any mathematical model which fuses the three dimensions of space and the one dimension of time into a single four-dimensional manifold. Spacetime diagrams can be used to visualize relativistic effects, such as why different observers perceive where and when events occur differently.
6 0
3 years ago
That 1.5 kg brick falls to the ground. What is the kinetic energy when the brick is moving at 26 m/s? Formula: Variables: Work w
Tresset [83]

Answer:

<h2>507 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

m is the mass

v is the velocity

From the question we have

k =  \frac{1}{2}  \times 1.5 \times  {26}^{2}  \\  =  \frac{1}{2}  \times 1.5 \times 676 \\  = 1.5 \times 338  \\ = 507

We have the final answer as

<h3>507 J</h3>

Hope this helps you

5 0
3 years ago
A large, cylindrical water tank with diameter 3.60 m is on a platform 2.00 m above the ground. The vertical tank is open to the
zysi [14]

To solve this problem it is necessary to apply the concepts related to the geometry of a cylindrical tank and its respective definition.

The volume of a tank is given by

V = \frac{\pi d^2}{4}h

Where

d = Diameter

h = Height

Considering that there are two stages, let's define the initial and final volume as,

V_0 = \frac{\pi d^2}{4}H

V_f = \frac{\pi d^2}{4}h

We know as well by definition that

1gal = 3.785*10^{-3}m^3

Then we have for the statement that

V_f = V_0 -1gal

V_f = V_0 - 3.785*10^{-3}

Replacing the previous data

\frac{\pi d^2}{4}h = \frac{\pi d^2}{4}H- 3.785*10^{-3}

\frac{\pi (3.6)^2}{4}h = \frac{\pi (3.6)^2}{4}(2)- 3.785*10^{-3}

Solving to get h,

h = 1.99963m

Therefore the change is

\Delta h = H-h

\Delta h = 2- 1.99963

\Delta h = 3.7*10^{-4}m=0.37mm

Therefore te change in the height of the water in the tank is 0.37mm

4 0
3 years ago
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