<span>1.5 times the number of carnation bushes.
If the number of carnation bushes is c.
R = 1.5c - 7
Hope this helps:-)</span>
Answer:
x = -3
y = -8
Step-by-step explanation:
2y = x - 13
3x = y - 1; let y = 3x + 1
substitute to solve for 'x':
2(3x + 1) = x - 13
6x + 2 = x - 13
5x + 2 = -13
5x = -15
x = -3
solve for 'y':
3(-3) = y - 1
-9 = y - 1
-8 = y
Answer:
C
Step-by-step explanation:
a is defined first as 5. So a = 5.
b is defined after the circle b = -2
a^2 = 5^2 = 25
B^4 =(- 2)^4 = 16
Therefore sqrt(a^2 * b^4) = sqrt(25 * 16) = sqrt(400) = 20
The answer is C
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude and n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)
The correct answer is option D. y = 2 sin (θ/2)
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<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude and n = 2π/period
<span>amplitude = 5 , period = 2π/n = 2π/2 = π
</span>
The correct answer is option B. Period: pi radians: Amplitude:5
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3. tan (2π/3) = tan 120° = -√3
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3
The correct answer is C. -sqrt3
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4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3
The correct answer is <span>B.-sqrt3/3</span>
First fold of a piece of paper produces two smaller pieces of paper
Second fold of the resulting pieces of paper produces 4 smaller pieces of paper.
Third fold of the resulting pieces of paper produces 8 smaller pieces of paper.
Thus, the five letter size pieces of paper folded three times produces 8 x 5 = 40 notes.
Thus, one notepad consists of 40 notes.
If someone wrote ten notes per day, then one notepad will last for 4 days.
