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viktelen [127]
2 years ago
6

Juan has 24 marbles and 6 bags Write a number sentence that shows how many marbles he can put in each bag if he puts the same nu

mber in each.

Mathematics
2 answers:
I am Lyosha [343]2 years ago
7 0
24 divided by 6=3 is the answer
Ludmilka [50]2 years ago
6 0
Y=24/6
24 divide by 6 equals 4 
so you can 6 bags with 4 marbles or 4 bags with 6 marbles

use a calculator 
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H(t)=(t+3)
Anarel [89]

Answer:

0

Step-by-step explanation:

h(t) = (t + 3)² + 5, -5 ≤ t ≤ -1

The average rate of change is the change in h over the change in t.

(h(-1) − h(-5)) / (-1 − (-5))

= ((-1 + 3)² + 5 − ((-5 + 3)² + 5)) / (-1 + 5)

= (4 + 5 − 4 − 5)) / 4

= 0

3 0
2 years ago
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maw [93]

Answer:possible

Step-by-step explanation:

6 0
2 years ago
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BRIANLIST ANSWER!! Please help on this one question ( if you’re good at this) thanks :))
ivann1987 [24]

Answer:

Step-by-step explanation:

(21²+10²)½ = 23.25= 23.3

5 0
2 years ago
The produce department of a grocery store sold 288 pounds of tomatoes. the weight represented 72% of the shipment the store rece
Zanzabum
288÷72=4 4x100=400 so there were 400 pounds of tomatoes origionally
7 0
2 years ago
Two friends race against each other in 100-meter and 800-meter races. Of the 200 races they ran this year, the wins, losses, and
docker41 [41]
<span>Let makes the table neater. event D= 100m, even E=800m
                                             (Event D) (Event E) 
A won the race (Event A)     30           50
B won the race (Event B)     60           25 
A and B tied (Event T)          10            25</span>

B did not win the race today. What length of the race was it more likely to have been? The question is asking in what event did the chance of B did not win(lose + ties) is more likely. Then, you need to determine the chance for B did not win <span>in both race.
Chance of B </span>did not win <span>100-m= 30+10/10=40%
</span>Chance of B did not win 800-m= 50+25/10=75%

The difference would be 75%-40%=35% more likely to lose 800-m race
4 0
3 years ago
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