Question

10. A bag contains 4 red balls, 6 green balls and some white balls. If the probability of not drawing a white ball in one draw be \(\frac{2}{3}\) then find the number of white balls.

Answer 1

Answer:

No of white balls = 5

Step-by-step explanation:

Given that,

Total no of red balls = 4

Total no of green balls = 6

The probability of not drawing a white ball in one draw be, $P=\dfrac{2}{3}$

We need to find the number of white balls. Let there are x balls.

The probability of drawing a white ball = 1 - the probability of not drawing a white ball

= 1 -2/3

= 1/3

Using the formula for solving probability of having a white ball.

$P=\dfrac{\text{favorable outcome}}{\text{total no of outcomes}}\\\\\dfrac{1}{3}=\dfrac{x}{4+6+x}\\\\\dfrac{1}{3}=\dfrac{x}{10+x}\\\\10+x=3x\\\\10=2x\\\\x=5$

Hence, there are 5 white balls.