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2 years ago

What is the frequency, in hertz, of blue light having a wavelength of 4.25 x 10-?m? Your answer should be

Chemistry

1 answer:

Naddik [55]2 years ago

7 0

Answer:

7.05*10^16(when wavelength =4.25*10^-9m)

Explanation:

c=wavelength *frequency (f)

i.e. f=c/wavelength =3*10^8/4.25*10^-9=7.05*10^16

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How many molecules of he are contained in a 10.0 l tank at 7.53 atm and 485 k?

ankoles [38]

Answer:

1.126 x 10^22

Explanation:

pV = nRT

7.53 x 10 = n x 8.31 x 485

n = (7.53 x 10) / (8.31 x 485) = 0.0187 moles

M = n x Avogadros number

0.0187 x 6.02 x 10^23 = 1.126 x 10^22

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2 years ago

Water has a higher boiling point than expected because

faust18 [17]

Because of the strong attractions between polar water molecules.

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2 years ago

2503(g) → 2502(g) O2(g)

Verizon [17]

Answer:

7.146

Explanation:

use the equilibrium equation

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2 years ago

What is the chemical name of the compound K2504?

12345 [234]

Answer:

Potassium sulfate

Explanation:

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2 years ago

Part III.The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (a

slega [8]

Answer:

$\large \boxed{\math{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

$\dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{3}{1}$

From Equation (2), the molar ratio of iodine to thiosulfate is

$\dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} = \dfrac{2}{1}$

Combining the two ratios, we get

$\text{Stoichiometric factor} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{IO}_{3}^{-}} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} \times \dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{2}{1} \times \dfrac{3}{1} = \mathbf{\dfrac{6}{1}}\\\\\text{The stoichiometric factor is $\large \boxed{\mathbf{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$}$

7 0

2 years ago