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anyanavicka [17]
3 years ago
6

What is the total oxidation state of the fluorine atoms

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
4 0

Answer:

-1

Explanation:

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Explain the meaning of the terms "saturated," "unsaturated," and "supersaturated"
dmitriy555 [2]
Saturated Solution: A solution with solute that dissolves until it is unable to dissolve anymore, leaving the undissolved substances at the bottom. Unsaturated Solution: A solution ( with less solute than the saturated solution )that completely dissolves, leaving no remaining substances. Supersaturated Solution.
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2 years ago
A 40.0 mL sample of 0.18 M HCI is titrated with 0.36 M CoHsNH2. Dctermine the pH at these points: At the beginning (before base
Whitepunk [10]

Answer:

at the beginning:

pH = 0.745

Explanation:

HCl is a strong acid, so:

  • HCl + H2O  → H3O+  +  Cl-

       0.18 M             0.18        0.18.....equilibrium

before base is added:

∴ [ H3O+ ] ≅ <em>C </em>HCl = 0.18 M

⇒ pH = - Log [ H3O+ ] = - Log ( 0.18 )

⇒ pH = 0.745

8 0
3 years ago
A certain metal M forms a soluble sulfate salt MSO, Suppose the left half cell of a galvanic cell apparatus is filled with a 3.0
bija089 [108]

Answer:

E = 0.062 V

Explanation:

(a) See the attached file for the answer

(b)

Calculating the voltage (E) using the formula;

E = - (2.303RT/nf)log Cathode/Anode

Where,

R = 8.314 J/K/mol

T = 35°C = 308 K

F- Faraday's constant = 96500 C/mol,

n = number of moles of electron = 2

Substituting, we have

E = -(2.303 * 8.314 *308/2*96500) *log (0.03/3)

   = -0.031 * -2

  = 0.062V

Therefore, the voltmeter will show a voltage of 0.062 V

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3 years ago
Name the two subatomic particles found in the nucleus.
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i can think of 3 subatomic particles found in a nucleus protons, neutrons, and electrons

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3 years ago
Read 2 more answers
Using the periodic table, complete the table to describe each atom. Type in your answers.
katovenus [111]

Answer:

A<em>=</em><em>4</em>

<em>B</em><em>=</em><em> </em><em>4</em><em>+</em><em>2</em><em> </em><em>=</em><em>6</em>

<em>C</em><em>=</em><em>C</em><em>arbon</em>

<em>D</em><em>=</em><em>10</em>

<em>E</em><em>=</em><em>22</em>

<em>F</em><em>=</em><em>Argon</em><em> </em>

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