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Ierofanga [76]
3 years ago
13

If an acid/base dissociates completely in water what type of substance is it? Does this mean the acid/base is dangerous?

Chemistry
1 answer:
hram777 [196]3 years ago
3 0

Answer:

1 strong acid

2 yes they are dangerous

Explanation:

Since nearly all of it is dissociated in water, it is called a strong acid.

2 yes Concentrated strong acids can cause severe and painful burns. The pain is due in part to the formation of a protein layer, which resists further penetration of the acid

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Present in a state where it molecules are far apart during a change of state it's molecules slow down which change of state has
blagie [28]

Answer:

The change of state that has occurred is from a gas to a liquid

<em>Note: The question is incomplete. The complete question is given blow.</em>

<em>H₂O is initially present in a state where its molecules are far apart. During a change of state, its molecules slow down. Which change of state has most likely taken place? </em>

<em>from a gas to a liquid </em>

<em>from a liquid to a gas </em>

<em>from a solid to a liquid </em>

<em>from a gas to a plasma</em>

Explanation:

Water can exists in three states: as gaseous water vapor, as liquid water, and as solid ice. Each of these states of water can be interconverted from one to another by the addition or removal of heat in a process known as change of state.

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Of the three states of water, the one in which the molecules are farthest apart is in the gaseous state. The molecules have high kinetic energy and move randomly while colliding with one another. When a heat is removed from these highly energetic molecules, the molecules slow down and lose some of their kinetic energy and a change of  occurs from gaseous to liquid state.

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The concentrations of the products at equilibrium are [pcl3] = 0.180 m and [cl2] = 0.250 m. what is the concentration of the rea
sineoko [7]
We have Kc = 4.2 x 10^-2 (given but missing in the question)
and When the balanced equation for this reaction is:
PCl5(g) ↔ PCl3(g) + Cl2(g)
so, according to the Kc formula:
Kc = the concentration of products / the concentration of the reactants
so, to get the concentration of the reactants in equilibrium, the concentration of the products / the concentration of the reactants should equal the Kc value which is given in the question (missing in your question).
So by substitution in Kc formula: 
Kc   = [PCl3]*[Cl2] / [PCl5]
4.2 x 10^-2 =  0.18 * 0.25 /[PCl5]
∴[PCl5] = 0.18*0.25 / 4.2x10^-2 = 1.07
So the concentration of the reactants in equilibrim = 1.07

4 0
3 years ago
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