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3 years ago

How does adding an atom affect the position of existing atoms or lone pairs?

2 answers:

8 0

Adding an atom will increase the repulsion between existing atoms and lone pairs. Added atom will result in bond pair-bond pair and bond pair-lone pair repulsion. The magnitude of the lone pair-bond pair repulsion is greater than the bond pair-bond pair repulsion. The added atom will change the electron geometry and bring about a distortion in the molecular geometry.

Alecsey [184]3 years ago

8 0

Answer: the addition of another atom changes the geometry of the molecule

Explanation:

Bond electron pairs and lone electron pairs always repel each other because electrons have the same charge (negative charge). Therefore, they tend to stay far away as possible. This gives the molecule a unique geometry. Then if we add another atom to this molecule, the geometry changes again to minimize the repulsion.

Further explanation:

In a molecule all the bond electron pairs and lone electron pairs repel each other because they have the same negative charge.

Therefore, these electron pairs tend to stay as far as possible, giving the molecule a unique geometry.

If we are going to add one more atom to this molecule, it means there comes another bond electron pair.

Then the existing bond and lone electron pairs tend to repel the new bond electron pair as well.

As a result, the geometry of the molecule changes in order to minimize the strain caused by repulsion.

Learn more:

1. Molecular geometry : brainly.com/question/11298860 : Answered by Sarajevo

2. Electron pair repulsions : brainly.com/question/7299065 : Answered by KaptainEasy

Key words: geometry, bond pair, lone pair, repulsion, electrons

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An artifact originally had 16 grams of carbon-14 present. the decay model upper a equals 16 e superscript negative 0.000121 ta=

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Given:

Initial amount of carbon, A₀ = 16 g

Decay model = 16exp(-0.000121t)

t = 90769076 years

To determine:

the amount of C-14 after 90769076 years

Explanation:

The radioactive decay model can be expressed as:

A = A₀exp(-kt)

where A = concentration of the radioactive species after time t

A₀ = initial concentration

k = decay constant

Based on the given data :

A = 16 * exp(-0.000121*90769076) = 16(0) = 0

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3 years ago

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True of false. A d-orbital lies in the x, y, and z area defined by the geometric axis of space.

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Answer:

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3 years ago

A nuclear reactor core must stay at or below 95 °C to remain in good working condition. Cool water at a temperature of 10 °C is

aliina [53]

Answer:

$\large \boxed{\text{67 000 g}}$

Explanation:

This is a problem in calorimetry — the measurement of the quantities of heat that flow from one object to another.

It is based on the Law of Conservation of Energy — Energy can be transformed from one type to another, but it cannot be destroyed or created.

If heat flows out of the reactor (negative), the same amount of heat must flow into the water (positive).

Since there is no change in total energy,

heat₁ + heat₂ = 0

The symbol for the quantity of heat transferred is q, so we can rewrite the word equation as

q₁ + q₂ = 0

The formula for the heat absorbed or released by an object is

q = mCΔT, where

m = the mass of the sample

C = the specific heat capacity of the sample, and

ΔT = T_f - T_i = the change in temperature

1. Equation

There are two heat flows in this problem,

heat released by reactor + heat absorbed by water = 0

q₁ + q₂ = 0

q₁ + m₂C₂ΔT₂ = 0

2. Data:

q₁ = -23 746 kJ

m₂ = ?; C₂ = 4.184 J°C⁻¹g⁻¹; T_f = 95 °C; T_i = 10 °C

3. Calculations

(a) Convert kilojoules to joules

$q_{1} = -\text{23 746 kJ} \times \dfrac{\text{1000 J}}{\text{1 kJ}} = -\text{23 746 000 J}$

(b) ΔT

ΔT₂ = T_f - T_i = 95 °C - 10 °C = 85 °C

(c) m₂

$\begin{array}{rcl}q_{1} + q_{2} & = & 0\\\text{-23 746 000 J} + m_{2} \times 4.184 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times 85 \, ^{\circ}\text{C} & = & 0\\\text{-23 746 000 J} + 356m_{2} \text{J$\cdot$g}^{-1} & = & 0\\356m_{2} \text{g}^{-1} & = & 23746000\\m_2&=& \dfrac{23746000}{\text{356 g}^{-1}}\\\\ & = & \textbf{67000 g}\\\end{array}\\$