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3 years ago

How does adding an atom affect the position of existing atoms or lone pairs?

2 answers:

8 0

Adding an atom will increase the repulsion between existing atoms and lone pairs. Added atom will result in bond pair-bond pair and bond pair-lone pair repulsion. The magnitude of the lone pair-bond pair repulsion is greater than the bond pair-bond pair repulsion. The added atom will change the electron geometry and bring about a distortion in the molecular geometry.

Alecsey [184]3 years ago

8 0

Answer: the addition of another atom changes the geometry of the molecule

Explanation:

Bond electron pairs and lone electron pairs always repel each other because electrons have the same charge (negative charge). Therefore, they tend to stay far away as possible. This gives the molecule a unique geometry. Then if we add another atom to this molecule, the geometry changes again to minimize the repulsion.

Further explanation:

In a molecule all the bond electron pairs and lone electron pairs repel each other because they have the same negative charge.

Therefore, these electron pairs tend to stay as far as possible, giving the molecule a unique geometry.

If we are going to add one more atom to this molecule, it means there comes another bond electron pair.

Then the existing bond and lone electron pairs tend to repel the new bond electron pair as well.

As a result, the geometry of the molecule changes in order to minimize the strain caused by repulsion.

Learn more:

1. Molecular geometry : brainly.com/question/11298860 : Answered by Sarajevo

2. Electron pair repulsions : brainly.com/question/7299065 : Answered by KaptainEasy

Key words: geometry, bond pair, lone pair, repulsion, electrons

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What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?

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First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation.

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis:

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3 years ago

What is the result of multiplying (2.5 × 1010) × (3.5 × 10-7)? Use the correct number of significant digits.

kow [346]

the result of multiplying (2.5 × 10¹⁰) and (3.5 × 10⁻⁷) is 8.8.10³ (cause the result must have 2 significant number)

<h3><em>Further Explanation</em> </h3>

Significant numbers are numbers obtained from the measurement results of exact numbers and the last number estimated

In scientific notation, all numbers are displayed before the big order is called significant numbers

the scientific notation can be described as:

a, ... x 10ⁿ

a, ... called an important number

10ⁿ is called a big order

Rules for significant numbers in general:

1. all non-zero numbers are significant numbers

2. a zero which is located between two non-zero numbers including a significant number

3. all zeros are located in the final row written behind the decimal point include significant number

4. zero decimal point is not significant number

In the question it is known that (2.5 × 10¹⁰) and (3.5 × 10⁻⁷) both have a significant number in a row 2.5 and 3.5

so that it meets the rule of significant numbers which is multiplication of 2 significant number produces numbers that have the fewest significant numbers, So the multiplication of the two will produce 2 significant number

So that we do the significant number then proceed a big order

1. Multiplication of significant number2.5 x 3.5 = 8.75

2. a big order multiplication 10¹⁰ x 10⁻⁷ = 10¹⁰⁻⁷ = 10³

So the result = 8.75.10³

Because the result must have 2 significant number , the result is 8.8.10³ (8.75 we round up)

<h3><em> Learn more</em></h3>

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3 years ago

Read 2 more answers

For the following experiments, identify the independent variable and the dependent variable:

faust18 [17]

Answer:

A) IV: number of hours DV: score

Explanation:

Coz,

IV- is the variable that u change

DV- is the variable that u test or measure

In this case, we need to change the hours of studying to see how studying for different hours [1 hr, 2hr, etc (( Independant variable coz we're changing the no. of hours)) ] is going to affect the student's score, and in the end, we are measuring the score of each student [this is the dependant variable].

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2 years ago