Respiration:
Glucose + oxygen ----> <u>Carbon dioxide + water (+energy)
</u>C6H12O6 + 6O2 ----> <u>6CO2 + 6H2O (+energy)</u>
Answer:
10. F
11. A
12. B
13. C
14. G
15. A
16. F
17. B
18. D
19. E
20. B
Explanation:
im sorry
ik some are probably incorrect
Explanation:
here's the answer to your question
<span>1 mole glucose gives 2 moles of ethanol
moles of glucose in 2.4 kg = 2400 / 180.18 = 13.320 moles
so moles of ethanol produced = 2* 13.32 = 26.64 moles
weight of ethanol 26.64 * 46.07
=1227.30 gm or 1.23 Kg</span>
<h3>
Answer:</h3>
3.6 × 10^24 molecules
<h3>
Explanation:</h3>
Concept: Moles and Avogadro's number
- We need to know that one mole of a compound has molecules equivalent to the Avogadro's number, 6.022 × 10^23.
- Therefore; 1 mole of a compound contains 6.022 × 10^23 molecules
In this case;
We are given 6 moles of Methane;
But 1 mole of methane = 6.022 × 10^23 molecules
Therefore;
Molecules = Number of moles × Avogadro's number
= 6 moles × 6.022 × 10^23 molecules/mole
= 3.613 × 10^24 molecules
= 3.6× 10^24 molecules
Thus, there are 3.6× 10^24 molecules in 6 moles of methane.
