Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
Answer:
Step-by-step explanation:
Answer:
for question a Tom is working at a faster pace because he is currently installing 7 windows a day while Suzanne is only installing 6 windows per day.
for question b Suzanne started off with more windows installed. I know this because the equation says that tom started with 3 windows installed and suzanne started with 5 windows installed.
Step-by-step explanation:
Answer:
6.8 cubic feet
Step-by-step explanation:
7.3/4=1.825, which is the side length, 1.825*1.825=20.2575 and then ypu divide 20.2575 by 3 because it is a pyramid and that gives you 6.7525
Velocity=Distance/Time
Time(t)=Distance/Velocity
☺☺☺☺
