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ExtremeBDS [4]
3 years ago
9

1.6x 10^5 in standard notation.

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0
The answer is 160,000. Since it's positive,move the decimal point 5 times to the right. 




ANSWER: 160,000
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Use substitution to determine if the solution is correct (PINK HIGHLIGHTED ONE!!!)
mart [117]

Answer:

It is not correct.

Step-by-step explanation:

If you plug 4 in for x, you get -2*4+5=13. This simplifies to: -8+5=13. This is an untrue statement since -8+5 is actually -3, not 13.

Hope this is helpful! :)

4 0
3 years ago
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Pls answer show work, At a store, notebooks are on sale for 78% off the regular price. The cost of a notebook is represented by
Assoli18 [71]

Answer:

<h2>C</h2>

Step-by-step explanation:

<h3> dont subtract the cost of the notebook by 0.78 while multiping it with the cost.</h3>
5 0
3 years ago
A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h
mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed  = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere  =\frac{2}{3}\pi r^3

Volume of a Cylinder =\pi r^2 h

Therefore:

The Volume of the Solid formed

=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Area of the Hemisphere =2\pi r^2

Curved Surface Area of the Cylinder =2\pi rh

Total Surface Area=

2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh

Cost of the Hemispherical Ends  = 2 X  Cost of the surface area of the sides.

Therefore total Cost, C

=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh

Recall: h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Therefore:

C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}

The minimum cost occurs at the point where the derivative equals zero.

C^{'}=\frac{-27840+32\pi r^3}{3r^2}

When \:C^{'}=0

-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518

Recall:

h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0
3 years ago
Help me with this plz
In-s [12.5K]

Step-by-step explanation:

180= 90+30+20x 90+30=120 180-120= 60

20x=60 x=3

3 0
3 years ago
2.4,1.6,3.2,0.3,1.5 each new piece of data is doubled calculate the mean
jekas [21]
Given the numbers above and those numbers only the mean would be 1.8
6 0
3 years ago
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