Answer:
bananas=$12.72
grapes=$9.48
oranges=$5.85
apples=$5.36
Step-by-step explanation:
To find the total cost for each fruit you would multiply the number of fruit by the cost.
bananas=3*4.24=$12.72
grapes=4*2.37=$9.48
oranges=3*1.95=$5.85
apples=2*2.68=$5.36
Answer:
true
Step-by-step explanation:
I can’t read the question, what is the question?
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
