the second duckling is wandering by 2.6 units distance than the first duckling .
<u>Step-by-step explanation:</u>
Here we have , Two ducklings wander away from the nest while their mother is away. The first duckling's displacement (distance and direction) from the nest is (12,5) The second duckling's displacement is (13,-8) . We need to find How much farther did the second duckling wander than the first duckling. Let's find out:
Let a = (12,5) and b =(13,-8)
The distance each duckling wandered is the magnitude of its displacement vector. Therefore, the expression Distance second duck wandered is given by :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the second duckling is wandering by 2.6 units distance than the first duckling .
Answer:
option A, option C, option D
Step-by-step explanation:
a) 1 ÷ m/6
can be written as
÷ 
b) sides in (m/6) will change if both has to multiply
c) 1 ÷ m/6
can be written as
1 * 6/m
1(
) and wont make change to answer. so matches with the question.
d)
1 ÷ m/6
1 * 6/m
1 * 6 * 
6 * 
6 ÷ m ..therefore true
e)
1 ÷ m/6
1 * 6/m
6/m ....does not match or can be converted to the following so wrong
- Therefore A, C, D are correct and B and E is wrong.
Answer:
There is 3 out of 4 chance you will get one head.
You are not guaranteed to get a head
Step-by-step explanation:
Lets determine the sample space
HH HT TH TT
These are the 4 things that can happen when we flip to coins
We want at least one head
3 of the 4 choices have at least 1 head
P (at least one head) = 3/4
Part A
Distribute the one-half.
1.24g + 0.87m + 0.98z
Part B
(29.68 - x) + 14.45
Or simplified to 44.13 - x
Part C
a = number of times at the store
b = gloves' price
c = hat's price