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3 years ago

The perimeter of the triangular park shown on the right is 11x - 7. What is the missing length?

Mathematics

1 answer:

AysviL [449]3 years ago

4 0

Answer:

6x-4

Step-by-step explanation:

the perimeter is the distance around the shape, we get this by adding all the sides, call the missing side y and set up an equation for the perimeter

11x-7 = 4x+2 + x-5 + y

solve for y

11x-7 = 5x -3 + y

11x-4 = 5x + y

6x-4 = y

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Can someone explain the process of getting to Angle A? I know the answer is 44.1 but I need to show my work so can someone show

dsp73

Answer:

Step-by-step explanation:

First you have to calculate CB in order to use sin law to calculate ∠A

CB= $\sqrt{18.4^{2} -13.2^{2} }$

CB=12.8(correct to nearest tenth)

After that, use sin law to calculate ∠A,

$\frac{18.4}{sin90} =\frac{12.8}{sinA}$ or $\frac{sin90}{18.4} =\frac{sinA}{12.8}$

sinA=0.695...

A=44.079...

=44.1(corrext to the nearest tenth)

Is that clear enough for you?

4 0

2 years ago

In a parallelogram, consecutive angles are

goldenfox [79]

Answer:

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3 years ago

What is A∪ϕ and A∩ϕ for a set A?

vodomira [7]

Answer:

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4 0

2 years ago

Find the value of y.

Phoenix [80]

$\boxed{y=6\sqrt{3}}$

<h2>Explanation:</h2>

For a better understanding of the problem I've built up two triangles from the given triangular shape. So these two triangles are similar. Therefore, we can solve this problem by using ratios and corresponding sides in this way:

$\frac{x}{3}=\frac{12}{x} \\ \\ x^2=36 \\ \\ x=\sqrt{36} \\ \\ x=6$

But our goal is to find y. Let's call w the height of the small triangle, then:

$w=\sqrt{6^2-3^2}=3\sqrt{3}$

Applying the concept of ratios again:

$\frac{y}{w}=\frac{x}{3} \\ \\ y=w \left(\frac{x}{3}\right) \\ \\ y=3\sqrt{3}\left(\frac{6}{3}\right) \\ \\ \boxed{y=6\sqrt{3}}$

<h2>Learn more:</h2>

Right triangle: brainly.com/question/10684799

#LearnWithBrainly

4 0

3 years ago

The graph of g(x)=(0.75)x+2 is shown.

Andrei [34K]

we are given

$f(x)=(0.75)^x+2$

For finding asymptote , we can find limit

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}((0.75)^x+2)$

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty} (0.75)^x+\lim_{x \to \infty} 2)$

now, we can solve it

$\lim_{x \to \infty} f(x)= 0+2$

$\lim_{x \to \infty} f(x)= 2$

so, horizontal asymptote is

$y= 2$ .............Answer

6 0

2 years ago