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ankoles [38]
3 years ago
14

Jose walked 5 miles in 2 hours. What was his walking rate in miles per hour?

Mathematics
2 answers:
tatyana61 [14]3 years ago
8 0
Jose was walking 2.5 miles per hour
balandron [24]3 years ago
3 0
It is 2.5 miles per hour
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Quadrilateral EFGH with diagonals EG and HF must be a parallelogram if (1) EF FG  and GH HE  (2) EG FH  (3) EG FH  (4) EF HG
qwelly [4]

Answer:

EF = HG and EF || HG

Step-by-step explanation:

A quadrilateral is a polygon shape with four sides and four angles.

A parallelogram is a quadrilateral with two pairs of parallel sides. The following are properties of a parallelogram:

  1. Opposite sides are equal and parallel.
  2. Opposite angles are equal to each other.
  3. Consecutive angles are supplementary
  4. The diagonals of a parallelogram bisect each other.

If Quadrilateral EFGH with diagonals EG and HF is a parallelogram then EF = HG and EF || HG

5 0
3 years ago
Tom works for a company his normal rate of pay 15 per hour
Brrunno [24]

The amount earned by Tom is the product of the <em>rate per</em> <em>hour and the number of hours</em> worked which is $90.

  • The amount earned per hour = $15

  • The number of hours worked = 6 hours

<u>The amount earned at the normal earning rate can be calculated thus</u> :

  • <em>Normal rate per hour × number of hours</em>

Amount earned = $15 × 6 = $90

Therefore, the amount earned by Tom after working for 6 hours at the normal rate is $90.

Learn more : brainly.com/question/18796573

3 0
2 years ago
Read 2 more answers
Must a function that is decreasing over a given interval always be negative over that same interval ? Explain
Leno4ka [110]
Check the picture below.

5 0
3 years ago
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Match each description when z = 9 + 3i. 1. Real part of z 2. Imaginary part of z 3. Complex conjugate of z 4. 3i - z 5. z - 9 6.
sergey [27]
1)\quad \Re(9+3i)=9\qquad\text{F}\\\\&#10;2)\quad \Im(9+3i)=3\qquad\text{E}\\\\&#10;3)\quad \overline{(9+3i)}=9-3i\qquad\text{D}\\\\&#10;4)\quad 3i-(9+3i)=3i-9-3i=-9\qquad\text{A}\\\\&#10;5)\quad 9+3i-9=3i\qquad\text{B}\\\\&#10;6)\quad 9-(9+3i)=9-9-3i=-3i\qquad\text{C}\\\\
5 0
3 years ago
Point Fis on line segment EG. EG = 100, EF = 4x - 20, and FG = 2x + 30. Write an equation that you would use to solve for x, the
andrew-mc [135]

Step-by-step explanation:

Line segment = EG

point on a line segment = F

EG = 100

EF = 4x - 20

FG = 2x + 30

a/q, EF + FG = EG

the equation is

4x - 20 + 2x + 30 = 100

now solution for x is

→ 4x - 20 + 2x + 30 = 100

→ 6x + 10 = 100

→ 6x = 100 - 10 = 90

→ x = 90/6 = 15

therefore, value of x is 15.

and according to given information

EF = 4x - 20 = 4(15) - 20 = 60 - 20 = 40

FG = 2x + 30 = 2(15) + 30 = 30 + 30 = 60

hope this answer helps you dear..take care and may u have a great day ahead!

3 0
3 years ago
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