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Mars2501 [29]
3 years ago
15

Which of the following non-hydrogen atom transitions does the photon have at its long wavelength?

Chemistry
1 answer:
suter [353]3 years ago
6 0

Answer:

The move from Level n=3 to Level n=2 has the long wavelength.

Explanation:

First, due to the selection rules, only transitions between adjacent levels are allowed, thus, only a transition between Level n=3 to Level n=2 or Level n=5 to Level n=4 are allowed. The two first options are wrong.

Second, analyzing the transition between Level n=3 to Level n=2 and the transition between Level n=5 to Level n=4 it is necessary to think in terms of the equation of the difference of energy for these type of transitions:

ΔE = \frac{h^{2}}{8.m.L}(n_{LUMO}^{2} -n_{HOMO}^{2} ) (1)

The difference in energy (ΔE) is directly proportional to the quadratic difference between the 'n' levels of transition. Therefore, If the transition occurs between smaller 'n' levels the difference of energy will be smaller too.

Also, the energy (ΔE) is inversely proportional to the wavelength (λ) so a smaller energy means a larger wavelength.

ΔE = c / λ (2)

Hence, the move from Level n=3 to Level n=2 has a long wavelength.

In order to calculate this wavelength is necessary to replace the data on equation (1) and (2).

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Leviafan [203]

Answer:

Krypton.

Explanation:

By Graham's Law:

Rate 1 / Rate 2 = sqrt M2 / sqrt M1

Molecular Mass for Neon  is 20.18

so we have:

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8 0
4 years ago
Use electron configurations to account for the stability of the lanthanide ions Ce4⁺ and Eu2⁺.
Inga [223]

Eu2+ is stable because of the two electrons in its outermost orbit and after losing 4 electrons. Ce +4 is stable

What are lanthanide ions?

All lanthanide elements form trivalent cations, Ln3+, whose chemistry is largely determined by the ionic radius, which decreases steadily from lanthanum to lutetium. These elements are called lanthanides because the elements in the series are chemically similar to lanthanum.

The Ce metal has the following electronic configuration: [Xe] 4f¹5d¹6s²

It obtains noble gas configuration after losing 4 electrons. Ce +4 is stable, so.

Eu's electronic setup is as follows.

[Xe] 4 f ⁷6s²

[Xe] 4 f ⁷

Eu2+ is stable because of the two electrons in its outermost orbit. Additionally stable is its +3 oxidation state. Ce⁺²

To learn more about lanthanides click on the link below:

brainly.com/question/12756990

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4 0
2 years ago
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bija089 [108]

Answer:

a. NH3+ HCl → NH4Cl

c. 2O3 → 3O2

Explanation:

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If we look at the species shown in the answer, there isn't any change in oxidation number as we move from left to right hence they are not redox reactions.

Redox reactions lead to change in oxidation number of species from left to right.

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3 years ago
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