Answer:
Theoretical yield of SO₂ is 1.56 × 10² g
Explanation:
Given data:
Mass of NiS₂ = 1.50 ×10² g
Mass of O₂ = 2.420 ×10² g
Theoretical yield of SO₂ = ?
Solution:
Chemical equation:
2NiS₂ + 5O₂ → 2NiO + 4SO₂
Moles of NiS₂:
Number of moles = mass/ molar mass
Number of moles = 1.50 ×10² g / 122.83 g/mol
Number of moles = 1.22 mol
Moles of O₂:
Number of moles = mass/ molar mass
Number of moles = 2.420 ×10² g / 32 g/mol
Number of moles = 7.56 mol
Now we compare the moles of SO₂ with NiS₂ and O₂.
NiS₂ : SO₂
2 : 4
1.22 : 4/2×1.22 = 2.44
O₂ : SO₂
5 : 4
7.56 : 4/5×7.56 =6.05
Moles of SO₂ produced by NiS₂ are less it will limiting reactant.
Mass of SO₂ = moles × molar mass
Mass of SO₂ = 2.44 mol × 64.07 g/mol
Mass of SO₂ = 156.33 g
So theoretical yield of SO₂ is 1.56 × 10² g
