Answer:
-66.88KJ/mol
Explanation:
It is possible to obtain the heat involved in a reaction using a calorimeter. Formula is:
q = -C×m×ΔT
<em>Where q is heat of reaction, C is specific heat capacity (4.18J/°Cg), m is mass of solution (100.0g) and ΔT is temperature change (23.40°C-22.60°C = 0.80°C)</em>
Replacing:
q = -4.18J/°Cg×100.0g×0.80°C
q = -334.4J
Now, in the reaction:
Ag⁺ + Cl⁻→ AgCl
<em>AgNO₃ as source of Ag⁺ and HCl as source of Cl⁻</em>
Moles that react are:
0.050L× (0.100mol /L) = 0.0050moles
If 0.0050 moles produce -334.4J. Heat of reaction is:
-334.4J / 0.0050moles = -66880J/mol = <em>-66.88KJ/mol</em>
1 mol of Carbon = 12 grams.
x mol of Carbon = 55 grams
12*x = 1 * 55
x = 55/12
x = 4.583333 mols of carbon
1 mol of anything is 6.02 * 10^23 atoms
4.58333333 mol = x
1/4.5833333 = 6.02 * 10^23/x
x = 4.58333* 6.02*10^23
x = 2.7591 * 10^23 Carbon atoms
i think it's I
I was confused by IV then search on gg and it said ZnSO4 should be Zn2SO4 instead but still im not sure Zn2SO4 is real
Answer:
This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.
Explanation:
May I have brainliest please? :)
Answer:
The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.
Explanation:
The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.
