1.291
1.251
1.341
1.331
1.321
1.311
1.281
1.271
1.261
If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.
<h3>What is the z-score?</h3>
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x - μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.
Then the probability that a cat will weigh less than 11 pounds will be
The value of z-score will be
z = (11 – 9) / 2
z = 1
Then the probability will be
P(x < 11) = P(z < 1)
P(x < 11) = 0.84134
Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.
More about the z-score link is given below.
brainly.com/question/15016913
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Answer:
Step-by-step explanation:
note:when you do perpendicular lines you must change the slope to the oppisite and reciporcal
2y+4x=12
2y-1/4x=12
1/4x+2y=12
Answer:
the number is 33 and 35 respectively
Step-by-step explanation:
The computation is shown below:
Let us assume X and X + 2 are the two consecutive odd integers
Now the equation is
(X ÷ 3) = ((X + 2) ÷ 7) + 6
(X ÷ 3) = (X + 2 + 6 × 7) ÷ 7
(X ÷ 3) = (X + 2 + 42) ÷ 7
(X ÷ 3) = (X + 44) ÷ 7
Now do the cross multiplication
7X = 3(X + 44)
7X = 3X + 132
4X = 132
X = 33
And, X + 2 = 33 + 2 = 35
hence, the number is 33 and 35 respectively
