Answer:
Part A)
m<BDG=m<MPQ
m<DBG=m<PMQ
m<DGB=m<PQM
Part B) 
Step-by-step explanation:
we know that
If two triangles are similar, then the ratio of its corresponding sides is equal and its corresponding angles are congruent
Part A)
we have that
the congruent angles are
m<BDG=m<MPQ
m<DBG=m<PMQ
m<DGB=m<PQM
Part B) The ratio of its corresponding sides is equal to
Applying parallel line postulate twice
36degree=3x degree +2y degree
126 degrees=12 x degree + 2y degree
So, the two equations are:
3x + 2y = 36
and
12x + 2y = 126
Eliminate x to solve for y
-(3x + 2y)= -(36)
-3x - 2y = -36
Combine the equations
(-3x - 2y)+ (12x + 2y) = (-36) + (126)
-3x -2y + 12x + 2y = -36 + 126
9x = 90
x = 10
Plug value of x back into to the equations to solve for y
3(10) + 2y = 36
30 + 2y = 36
2y =6
y = 3
Optional
Plug x into the other equation to check for error
12(10) +2y = 126
120 + 2y =126
2y = 6
y = 3
Answer:
n-5=2n+9
Step-by-step explanation:
Answer:
m = (y-6)/x
Step-by-step explanation:
To solve for m we want to get m by itself on one side of the equals sign, with everything else on the other side. First we subtract b from both sides, to get it out of the right side of the equation:
y - 6 = mx + 6 - 6
y - 6 = mx
Now we divide both sides by x, to get m completely by itself:
(y-6)/x = (mx)/x
(y-6)/x = m
So m is equal to (y-6)/x.
Answer:
IDK how to do this one sorry
Step-by-step explanation:
