Answer:
28
Length=2(x-1)
Width=5
Area=length*width = (2(x-1))(5) = (2x-2)(5) = 10x-10
29
His reasoning is illogical because whether or not an expression has a term that is being subtracted isn't relevant; technically there are an infinite amount of ways to represent a value. Plus you can just compute the expressions and see that they're equal:
6x-2x+4 = 4x+4
4(x-1) = 4x+4
30
The two expressions are equal because when you compute the expression 4(n+3)-(3+n) , you get 3n+9:
4(n+3)-(3+n) = 4n+12-3-n = 3n+9
31
The two expressions are equal because when you compute the expression 2(2n-1), you get 4n-2.
2(2n-1) = (2)(2n)+(2)(-1)=4n-2
32
5(g+14)=(5)(g)+(5)(14)=5g+70
The expressions aren't equal as 5(g+14) equates to 5g+70 and 5g+70≠5g+14.
28. THATS THE CORRECT ANSWER
Answer:
143.864
Step-by-step explanation:
The force the same object will exert if it accelerates at a rate of 7 m/s² is 35N
From the question,
We are to determine the force the object will exert.
From the information,
Newton’s Second Law of Motion states that the acceleration of an object is directly proportional to the force exerted on the object
Let acceleration be a
and
Force be F
Then we can write that,
F ∝ a
Then,
Introducing the constant, mass, m
We get
F = ma
Now, we will determine the mass of the object
F = 15 N
a = 3 m/s²
Putting the parameters into the formula, we get
15 = m × 3
∴ m = 15 ÷ 3
m = 5 kg
The mass of the object is 5 kg.
Now, to determine the force the same object will exert if it accelerates at a rate of 7 m/s²
That is,
a = 7 m/s²
and
m = 5 kg
Putting the parameters into the formula, we get
F = 5 × 7
F = 35 N
Hence, the force the same object will exert if it accelerates at a rate of 7 m/s² is 35N
Learn more here: brainly.com/question/13590154
Answer: 57 ft
Step-by-step explanation: Because drawing it up, we can make a right angled triangle with the right angle between the height of the man in the building and the distance out from the building of the man in the street, and the 35 degrees between the line connecting the man in the street with the man in the building, and the line out from the building of the man in the street. Then, tan of the 35 degree angle is = to opposite (40ft)/adjacent (to solve for). By cross multiplication, the A or adjacent (dist out from the building) = 40/0.7 (0.7 = tan of 35 degrees) so the answer is 57 ft.
