Question

In △ABC the angle bisectors drawn from vertices A and B intersect at point

Answer 1

Answer:

105 Degrees

Step-by-step explanation:

Lets take x as the number we need to find

angle bisector splits the number in half so 50 and 100 divided by 2 = 25 and 50. 25 + 50 = 75 so we know 75 + x = 180

180 - 75 = x

105 = x

The answer is 105 degrees

Answer 2

The measure of ∠ADB will be 105°

Explanation

According to the below diagram, the angle bisectors of ∠A and ∠B are intersecting at point D.

Given that, the measures of $\angle BAC = 50$° and $\angle ABC=100$°

So, $\angle DAB= \frac{50}{2}=25$° and $\angle DBA= \frac{100}{2}= 50$°

Now in triangle ADB, the sum of all three angles is 180°

So,  $\angle ADB= 180-(\angle DAB + \angle DBA)= 180-(25+50)=180-75= 105$

Thus, the measure of ∠ADB will be 105°