Attached the solution with work shown.
Answer:

Step-by-step explanation:
Given:


Need:

First, let's look at the identities:
sum: 
difference: 
The question asks to find sin(A - B); therefore, we need to use the difference identity.
Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.
sin(A) = 
cos(A) = 
sin(B) = 
cos(B) = 
Plug these values into the difference identity formula.


Multiply.

Add.

This is your answer.
Hope this helps!
If you are working with time or days, you can't put in a negative value because if you are doing an experiment, you can't go back in time to do that experiment to gather data. (Time for the most part considered to be an input value so that's why I used it as an example.)