What is the absolute value of -13

Mathematics

2 answers:

dalvyx [7]3 years ago

6 0

It would be positive 13. Even if its negative or positive it will always be positive. For example, |-7|= 7 |7|=7

MrRissso [65]3 years ago

5 0

Answer:

Step-by-step explanation:

An absolute value measures the distance of that number from zero.

For example, in this case, both the number 13 and -13 have an absolute value of 13 because both of them are 13 spaces away from zero, simply in different directions.

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What angles do perpendicular lines form

Natasha2012 [34]

Answer:

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7 0

3 years ago

Divide 7/24 by 35/48 and reduce the quotient to the lowest fraction

tiny-mole [99]

$\frac{7}{24}$ ÷ $\frac{35}{48}$
Multiply $\frac{7}{24}$ by the reciprocal of $\frac{35}{48}$ , which is $\frac{48}{35}$

= $\frac{7}{24}$ × $\frac{48}{35}$
= $\frac{336}{840}$

We can simplify it further:
The greatest common factor here is 168
$\frac{336/168}{840/168}$

= $\frac{2}{5}$

4 0

3 years ago

A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 65m/s in 5 seconds what

artcher [175]

The acceleration is defined as the ratio between the change in velocity and the time elapsed to perform such a change.

These "changes" are indicated with the capital greek letter delta, $\Delta$ , and when you write $\Delta x$ you mean the difference between the finial and the inital values of the variable x:

$\Delta x = x_{\text{fin}} - x_{\text{init}}$

So, the acceleration is defined as

$a = \dfrac{\Delta v}{\Delta t} = \dfrac{v_{\text{fin}} - v_{\text{init}}}{t_{\text{fin}} - t_{\text{init}}}$

In this case, the initial velocity is 35, the final velocity is 65. Assuming we start the clock at the beginning of the observation, the inital time is 0 and the final time is 5. So, we have

$a = \dfrac{65-35}{5-0} = \dfrac{30}{5} = 6$ m/s^2