Answer:
Θ = 46°
Step-by-step explanation:
the angle between a tangent and a radius at the point of contact is 90° , so
∠ ABO = 90°
since OB = OD ( radii of circle ) then Δ BOD is isosceles and
∠ OBD = ∠ ODB = 22°
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ AOB is an exterior angle of the triangle , then
∠ AOB = 22° + 22° = 44°
the sum of the 3 angles in Δ AOB = 180° , then
Θ + 44° + 90° = 180°
Θ + 134° = 180° ( subtract 134° from both sides )
Θ = 46°
2x+1 = x-5
-x -x
X+1 = -5
-1 -1
X = -6
2(-6) +1= y
-12+1= y
-11 = y
-11 = -12+1
-11 = -6-5
2,2 is 3,4 away from 5,6 and 3²+4²=25=5² so CD=5
Answer:
D
Step-by-step explanation:
Trust me I have big brain
