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pantera1 [17]
3 years ago
9

at 7 p.m. last night, the temperature was 10 degree. at 7 a.m. the next morning the temperature was -2 degree. By how much did t

he temperature change from 7 p.m. to 7 a.m.? By how much did it changed each hour?
Mathematics
2 answers:
Brums [2.3K]3 years ago
5 0
Change in temperature =  -2 - 10 = -12 degrees

rate of change per hour = -12 / 12 = -1 degree.
xxTIMURxx [149]3 years ago
4 0
The temperature changed by 12 degrees in 12 hours meaning one degree per hour.
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Ivanshal [37]

Answer:

x=4\sqrt{3},\:x=-4\sqrt{3} are the roots.

Step-by-step explanation:

x=4\sqrt{3},\:x=-4\sqrt{3}

Considering the expression

x^2\:-\:48

Solving

x^2-48=0

x^2-48+48=0+48

x^2=48

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{48},\:x=-\sqrt{48}

Solving

x=\sqrt{48}

  = \sqrt{2^4\cdot \:3}

  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

  = \sqrt{3}\sqrt{2^4}

  \mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^m}=a^{\frac{m}{n}}

  \sqrt{2^4}=2^{\frac{4}{2}}=2^2

  =2^2\sqrt{3}

  =4\sqrt{3}

So,

x=4\sqrt{3}

Similarly,

x=-\sqrt{48}=-4\sqrt{3}

Therefore, x=4\sqrt{3},\:x=-4\sqrt{3} are the roots.

Keywords: roots, expression

Learn more about roots from brainly.com/question/3731376

#learnwithBrainly

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3 years ago
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Answer:

70.5

Step-by-step explanation:

Set of Data (Prioritized):

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To find the median:

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Answer:

Ah Thanks so much

Step-by-step explanation:

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3 years ago
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Answer:

Pepper Jackie still has 5.8

Step-by-step explanation:

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3 years ago
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swat32

Answer:

<em>Riko is wrong because she uses the wrong formula.</em>

Step-by-step explanation:

Given the coordinate points (-2, -3) and (2, -5)

We are to find the distance between the two points

Using the formula:

D = √(x2-x1)²+(y2-y1)²

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D = √16 + 4

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