Answer:
V=Bh
Step-by-step explanation:
thare are muliple ways to use this equation like V=Bh
V=1/2Bh or V=1/3Bh
Answer:
Cost of a single Mucho beef burrito: 
Cost of a double Mucho beef burrito: 
Step-by-step explanation:
<h3>
The exercise is: "The Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant sold 16 orders of the single Mucho variety and 22 orders of the double Mucho. If the restaurant sold $231 Worth of beef burritos last week and the single neutral kind cost $1 Less than the double Mucho, how much did each type of burrito cost?"</h3>
Let be "x" the the cost in dollars of a single Mucho beef burrito and "y" the cost in dollars of a double Mucho burrito.
Set a system of equations:
To solve this system you can apply the Substitution Method:
1. Substitute the second equation into the first equation and solve for "y":
2. Substitute the value of "y" into the second equation and evaluate in order to find the value of "x":
$10.50a + $3.75b = $2,071.50
It is given that b = 82
Therefore - $10.50a + ($3.75)(82) = $2,071.50
or $10.50a + $307.50 = $2,071.50
$10.50a = $2,071.50 - $307.50 = $1,764.00
Therefore - a (number of adult tickets sold) = $1,764.00/$10.50 = 168 tickets
It can be made through straight line or curved lines.
We have the following information:
first urn: 6 green balls and 3 red ones
total: 6 + 3 = 9
second urn: 3 green, 3 white and 3 red
total: 3 + 3 + 3 = 9
third urn: 6 green, 1 white and 2 red
total: 6 + 1 + 2 = 9
a) A green ball is more likely to be obtained, since there are more green balls than red balls, which makes the probability higher.
b) probability of drawing a green, red and white ball.
first urn:
green = 6/9 = 66.66%
red = 3/9 = 33.33%
white = 0/9 = 0%
second urn:
green = 3/9 = 33.33%
red = 3/9 = 33.33%
white = 3/9 = 33.33%
third urn:
green = 6/9 = 66.66%
red = 2/9 = 22.22%
white = 1/9 = 11.11%
c) it would be chosen where the probability of drawing green would be the highest, which means that it would be possible both in the first and in the third ballot box, the probability is equal 66.66%
d) without a green ball, the third ballot box would look like this:
5 green balls, 2 red balls and 1 white ball, with a total of 8.
The probability of drawing would be:
green = 5/8 = 62.5%
red = 2/8 = 25%
white = 1/8 = 12.5%
