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Answer: 7
Step-by-step explanation:
By the angle bisector theorem,
Answer:
The probability that the test is taken an even number of times is 0.30.
Step-by-step explanation:
The probability that a student passes the driving test at any attempt is,
<em>p</em> = 4/7.
The event of a student passing in any attempt is independent of each other.
The probability that the test is taken an even number of times is:
P (even number of tests) = P (Passing in the 2nd attempt)
+ P (Passing in the 4th attempt)
+ P (Passing in the 6th attempt) ...
If a student passed in the 2nd attempt it implies that he failed in the first.
Then, P (Passing in the 2nd attempt) =
Similarly, P (Passing in the 4th attempt) = , since he failed in the first 3 attempts.
And so on.
Compute the probability of an even number of tests as follows:
P (even number of tests) =
The result follows a Geometric progression for infinite values.
The sum of infinite GP is:
The probability is:
P (even number of tests) =
Thus, the probability that the test is taken an even number of times is 0.30.
Say you have 95 over 10. You put how many times 10 goes into 95, which is 9. Then you have 5 left over. You take 5 and put it over 10. You can simplify that to 1 over 2. Your mixed number would then be 9 and 1/2.
