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eduard
3 years ago
15

Thermal radiation gets its name because __________.

Physics
1 answer:
snow_tiger [21]3 years ago
7 0

its spectrum depends on the temperature of the object emitting it.

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As an electron moves, what does it make or cause ?
jolli1 [7]
It causes or makes a magnetic field.
3 0
3 years ago
If the acceleration of a motorboat is 4.0 m/s2, and the motorboat starts from rest, what is its velocity after 6.0 s?
umka2103 [35]

Answer:

The velocity of the motorboat after 6s is 24 m/s.

Explanation:

Given;

acceleration of the motorboat, a = 4.0 m/s²

initial velocity of the motorboat, u = 0

time of motion of the motorboat = 6s

Apply the following kinematic equation to determine the velocity of the motorboat after 6 ;

v = u + at

v = 0 + (4 x 6)

v = 24 m/s

Therefore, the velocity of the motorboat after 6s is 24 m/s.

6 0
3 years ago
Two spheres A and B are projected off the edge of a 1.0 m high table with the same horizontal velocity . sphere A has a mass of
Arte-miy333 [17]

Answer:

c. because A will land first becuase its heavier

Explanation:

3 0
3 years ago
6. Протон с кинетична енергия Ek = 1,6.10 J, който се
anzhelika [568]

Answer:

Tahukah kamu, mengapa motor berhenti di depan lampu merah?

karena motornya direm. Coba kalau nggak direm bisa bahaya tuh.

Tebak binatang apa yang jago renang?

Bebek. Kalau ikan bukan renang tapi menyelam

Kenapa di rel kereta api ditaruh batu?

Soalnya kalau ditaruh duit nanti pada diambil.

3 0
3 years ago
(a) Two ions with masses of 4.39×10^−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic fiel
sammy [17]

Answer:

Part a)

R_1 = 0.072 m

Part b)

R_2 = 0.036 m

Part c)

d = 0.072 m

Explanation:

Part a)

As we know that the radius of the charge particle in constant magnetic field is given by

R = \frac{mv}{qB}

now for single ionized we have

R_1 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(1.6 \times 10^{-19})(0.301)}

R_1 = 0.072 m

Part b)

Similarly for doubly ionized ion we will have the same equation

R = \frac{mv}{qB}

R_2 = \frac{(4.39\times 10^{-27})(7.92 \times 10^5)}{(3.2 \times 10^{-19})(0.301)}

R_2 = 0.036 m

Part c)

The distance between the two particles are half of the loop will be given as

d = 2(R_1 - R_2)

d = 2(0.072 - 0.036)

d = 0.072 m

6 0
3 years ago
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