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3 years ago

Gravity causes all falling objects to accelerate at a rate of 98 m/s2. O True O False

Physics

1 answer:

aleksandrvk [35]3 years ago

8 0

It’s true the acceleration of falling objects on earth due to gravity is 98ms2

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The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.320 with the floor. If

mart [117]

Answer: 29.50 m

Explanation: In order to calculate the higher accelation to stop a train without moving the crates inside the wagon which is traveling at constat speed we have to use the second Newton law so that:

f=μ*N the friction force is equal to coefficient of static friction multiply the normal force (m*g).

f=m.a=μ*N= m*a= μ*m*g= m*a

then

a=μ*g=0.32*9.8m/s^2= 3.14 m/s^2

With this value we can determine the short distance to stop the train

as follows:

x= vo*t- (a/2)* t^2

Vf=0= vo-a*t then t=vo/a

Finally; x=vo*vo/a-a/2*(vo/a)^2=vo^2/2a= (49*1000/3600)^2/(2*3.14)=29.50 m

5 0

3 years ago

An inductor has inductance of 0.260 H and carries a current that is decreasing at a uniform rate of 18.0 mA/s.

nignag [31]

Answer:

The self-induced emf in this inductor is 4.68 mV.

Explanation:

The emf in the inductor is given by:

$\epsilon = -L\frac{dI}{dt}$

Where:

dI/dt: is the decreasing current's rate change = -18.0 mA/s (the minus sign is because the current is decreasing)

L: is the inductance = 0.260 H

So, the emf is:

$\epsilon = -L\frac{dI}{dt} = -0.260 H*(-18.0 \cdot 10^{-3} A/s) = 4.68 \cdot 10^{-3} V$

Therefore, the self-induced emf in this inductor is 4.68 mV.

I hope it helps you!

6 0

3 years ago

What is Force & how many types of Force express with example <br><br><br><br>

ehidna [41]

Answer:

The force is pull or push acting on the body which tends to change its state of rest or of motion is called force.

There are two types of force:

1.Contact force

2. Non-Contact

7 0

3 years ago

We dont see objects. We see the light ____ off objects.

Romashka [77]

The answer is BBBBBBBBB

4 0

3 years ago

Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of 6.88 × 1014 Hz. The speed of li

Nezavi [6.7K]

Answer: 430 nm.

Explanation:

The relation of wavelength and frequency is:

Formula used : $\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency = $6.88\times 10^{14}Hz$

$\lambda$ = wavelength = ?

c = speed of light = $3.00\times 10^{8}m/s$

Now put all the given values in this formula, we get

$6.88\times 10^{14}=\frac{3.00\times 10^{8}m/s}{\lambda}$

$\lambda=\frac{3.00\times 10^{8}m/s}{6.88\times 10^{14}}=0.43\times 10^{-6}m=430m$ $(1nm=10^{-9}m)$

Thus the wavelength (in nm) of the blue light emitted by a mercury lamp is 430 nm.

6 0

3 years ago