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Mama L [17]
3 years ago
6

At 6:00 A.M. the temperature was 33°F. By noon the temperature had increased by 10°F and by 3:00 P.M. it had increased another 1

2°F. If at 10:00 P.M. the temperature had decreased by 15°F, how much does the temperature need to rise or fall to return to the original temperature of 33°F?
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
5 0

Answer:

The temperature needs to decrease by 7°F to return to the original temperature.

Step-by-step explanation:

The temperature starts at 33 degrees then increases by 10 then 12 then decreases by 15 which will equal 40.

33 + 10 = 43

43 + 12 = 55

55 - 15 = 40

40 - 33 = 7

The temperature needs to decrease by 7 degrees.

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vlada-n [284]

Answer:

Area of regular pentagon is 238.95 square inches.

Step-by-step explanation:

Given a regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.

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3 years ago
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The distance dd is 11 mm. What is the perimeter of the figure? Round to the nearest tenth.
Kisachek [45]

Answer:

P = 157.1 mm

Step-by-step explanation:

The perimeter of the figure = Circumference of circle + perimeter of square

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3 years ago
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