At 6:00 A.M. the temperature was 33°F. By noon the temperature had increased by 10°F and by 3:00 P.M. it had increased another 1
2°F. If at 10:00 P.M. the temperature had decreased by 15°F, how much does the temperature need to rise or fall to return to the original temperature of 33°F?
So, you just have to recognize the line splitting the circle in half, line LJ. So, if JC (arc) is 94, then do 180-94=86. ∠LJC is an inscribed angle, so it's half of 86, which is 43°.
