Answer:
a = -86.
Step-by-step explanation:
By the Factor Theorem, if x + 4 is a factor then P(-4) = 0, so:
P(-4) = 2(-4)^3 - 11(-4)^2 + a(-4)- 40 = 0
-128 - 176 - 4a - 40 = 0
-4a = 128 +176 + 40
-4a = 344
a = -86.
Answer:
x: 3/4, 1 1/4, x
y:6 1/4, 7 3/4, y
Step-by-step explanation:
Answer:
since there is no image attached I can't see what weight they could be labeled but since the scale is even the weights must be the same number weight
Step-by-step explanation:
hope this helped!
A function for which every element of the range of the function corresponds to exactly one element of the domain. One-to-one is often written 1-1. Note: y = f(x) is a function if it passes the vertical line test.
So it tells us that g(3) = -5 and g'(x) = x^2 + 7.
So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))
now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16
Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84
So we have our linear approximation for the two.
If you wanted to, you could check your answer by finding g(x). Since you know g'(x), take the antiderivative and we will get
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35
So just to check our linear approximations use that to find g(2.99) and g(3.01)
g(2.99) = -5.1597
g(3.01) = -4.8397
So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer. Not a bad method if you ever need to use it.
