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Troyanec [42]
3 years ago
9

On March 24, 1989, the Exxon Valdez oil tanker ran aground and leaked millions of gallons of oil into Prince William Sound. The

spill covered approximately 11,000 square miles of ocean. The oil spread out in a circular pattern and the radius increased by 0.10 mph. Use π = 3.14. At this rate, how many hours did it take for oil to cover the area?

Mathematics
2 answers:
vaieri [72.5K]3 years ago
6 0

Answer: B

592 hours

Step-by-step explanation:

Tema [17]3 years ago
3 0

Answer:

592 hours

Step-by-step explanation:

Given

Area = 11000m^2

Radius = 0.10m/h

Required

Determine the time taken to cover the area

Since, the oil formed a circular pattern; the question will be answered using area of a circle

Area = \pi r^2

Let t represent the time take to cover 11000m²;

The relationship between these parameters is:

11000 = \pi * (0.10t)^2

Substitute 3.14 for π

11000 = 3.14 * (0.10t)^2

Divide both sides by 3.14

\frac{11000}{3.14} = \frac{3.14 * (0.10t)^2}{3.14}

\frac{11000}{3.14} =(0.10t)^2

3503.18471338 = (0.10t)^2

Take square root of both sides

\sqrt{3503.18471338} = \sqrt{(0.10t)^2}

\sqrt{3503.18471338} = 0.10t

59.1877074516 = 0.10t

Divide both sides by 0.10

\frac{59.1877074516}{0.10} = \frac{0.10t}{0.10}

\frac{59.1877074516}{0.10} = t

591.877074516 = t

t = 591.877074516

t = 592\ hours <em>(</em><em>Approximated)</em>

<em>Hence, it'll take approximately 592 hours to cover the given area</em>

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Please help!
erik [133]
For the answer to the question above, 
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3 

<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>

<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>

<span>1 + 9x + 36x^2 + 84x^3 </span>

<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>

<span>(1+x) = 0.98 </span>

<span>x = 0.98 - 1 = -0.02 </span>

<span>Substituting: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>

<span>approximation = 0.834 </span>

<span>Checking the real value in your calculator: </span>

<span>(0.98)^9 = 0.834 </span>

<span>So you have approximated correctly. </span>

<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>

<span> (0.98)^9 = 0.8337477621 </span>

<span>So it is correct to 4</span>
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