Answer:
The area of A is nine times the area of B.
Step-by-step explanation:
Answer:
T
Step-by-step explanation:
Answer:
940.8 N
1254.4 N
Step-by-step explanation:
I would think the questions would be to calculate the forces at the top of the cube and at the sides. Thus:
On the top:
F = pressure * area
P = density * gravity * height
the height would be:
1m - 0.4m = 0.6m
replacing:
P = 1000 * 9.8 * 0.6 = 5880
A = (0.4) ^ 2 = 0.16
F = 5880 * 0.16
F = 940.8 N
On the sides:
dF = d * g * h * dA
dA = 0.4 * dh replacing
dF = 1000 * 9.8 * h * 0.4 * dh
dF = 3920 * h * dh
We integrate both sides and we have:
F = 3920 * (h ^ 2/2), h = 0.6 up to h = 1
F = (3920/2) * (1 ^ 2 - 0.6 ^ 2)
F = 1254.4 N
4x+6y=8
3x+y=9
y = 9 - 3x
4x + 6(9-3x) = 8
4x + 54 - 18x = 8
14x = 46
x = 23/7
y = 9 - 3(23/7)
y = 9 - 69/7
y = - 6/7
For the answer to the question above,
1 + nx + [n(n-1)/(2-factorial)](x)^2 + [n(n-1)(n-2)/3-factorial] (x)^3
<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>
<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>
<span>1 + 9x + 36x^2 + 84x^3 </span>
<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>
<span>(1+x) = 0.98 </span>
<span>x = 0.98 - 1 = -0.02 </span>
<span>Substituting: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>
<span>approximation = 0.834 </span>
<span>Checking the real value in your calculator: </span>
<span>(0.98)^9 = 0.834 </span>
<span>So you have approximated correctly. </span>
<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>
<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>
<span> (0.98)^9 = 0.8337477621 </span>
<span>So it is correct to 4</span>