Question

Five times the smallest of three consecutive odd integers is seven more than twice the largest. Find the largest integer.

Answer 1

Hey there!

Let's write this as a system of equations. We will use s, m, and L for our integers.

5s=2L+7

s= L-4 (Consecutive ODD integers)

We can plug our s value into the first equation and solve for L, our largest integer.

5(L-4)=2L+7

5L-20=2L+7

3L-20=7

3L=27

L=9

Therefore, our largest integer is 9.

I hope this helps!