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2 years ago

What is the equation of the line that passes through the point (6,3) has a slope of -1/3

Mathematics

1 answer:

DerKrebs [107]2 years ago

5 0

Answer:

y = -1/3x + 5

Step-by-step explanation:

y = mx + b

so y = 3, x = 6, m = -1/3

then 3 = (-1/3)6 + b

3 = -2 + b

b = 5

so y = -1/3x + 5

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It is the Coefficient

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I can’t seen the question so it is hard to answer

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Answer:

Part a) $AB=15\ cm$

Part b) $AB=11.1\ cm$

Part c) $AB=3/5\ cm$

Part d) $AB=3s\ cm$

Step-by-step explanation:

see the attached figure to better understand the question

we know that

To find the length of the image after a dilation, multiply the length of the pre-image by the scale factor

Part a) we have

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3 years ago

1. The price of a TV is $295. The price of a

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The price of the projector is $1,180.

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3 years ago

The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented

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As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

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$d= \frac{a^{2}}{c}$

Here the directrix line is given as : x= 2304/50

Thus, $\frac{a^{2}}{c} = \frac{2304}{50}$

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